Question

我有一个Play网络应用程序向服务器发出HTTP请求。

请求顺利：我收到200状态代码和Content-type =＆＃34; application / xml＆＃34;的回复。

如果我打印到stdout响应主体，我会看到一个结构良好的Xml doc。

但是，如果我尝试从响应中创建org.w3c.dom.XML文档使用WSResponse.asXml（），该方法返回一个空文档。

这些是我的代码的相关部分：

private WSResponse sendPostRequest(String url, String body) {

    WSRequest request = WS.url(url);

    request.setHeader("Content-type", "application/x-www-form-urlencoded");

    return request.post(body).get(5000L);
}

并且：

public Result requestDefaultImport() {

    String url = "some_url";
    String body = "some_body";

    WSResponse response = sendPostRequest(url, body);

    System.out.println(response.getBody()); //prints well-formed Xml

    Document xmld = response.asXml(); 
    System.out.println(xmld); //prints: #[null document]


    return ok();
}

我做错了什么？

Answer 1

试试这段代码：

Document doc = request().body().asXml();
Source source = new DOMSource(doc);
StringWriter stringWriter = new StringWriter();
StreamResult result = new StreamResult(stringWriter);
TransformerFactory factory = TransformerFactory.newInstance();
javax.xml.transform.Transformer transformer = factory.newTransformer();
transformer.transform(source, result);
String xmlStr = stringWriter.getBuffer().toString();
System.out.println(xmlStr);

或者如果从SOAP中消费：

Document doc = soapBody.extractContentAsDocument();
Source source = new DOMSource(doc);
StringWriter stringWriter = new StringWriter();
Result result = new StreamResult(stringWriter);
TransformerFactory factory = TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer();
transformer.transform(source, result);
strSoapBody = stringWriter.getBuffer().toString();

Answer 2

据我所知，你正在

打印一个字符串

System.out.println(response.getBody());

但是，您正在

打印org.w3c.dom.Document

 System.out.println(xmld);

可以在

找到将Document转换为字符串的解决方案

How do I convert a org.w3c.dom.Document object to a String?

Play Framework：解析服务器的响应，因为Xml返回null文档

2 个答案: