Python数字猜测游戏需要帮助避免在“猜测数量”中计数​​重复

Question

我是学习Python的新手，我正在构建一个非常简单的猜数游戏。用户猜测1-100之间的数字，并且给出关于他们的猜测是否太低或太高的反馈。当他们正确猜出数字时，程序会告诉他们他们采取了多少猜测。我需要帮助的是：告诉用户他们猜到重复号码的时间是否已经输入。我还想排除最终猜测计数中的任何重复猜测。最简单的方法是什么？

到目前为止，这是我的游戏：

import random

print("Guess a number between 1-100")

the_number = random.randint(1, 100)
guess = int(input(""))
tries = 0

while guess != the_number:
    if guess > the_number:
        print("Lower")
    if guess < the_number:
        print("Higher")

    guess = int(input("Guess again: "))
    tries += 1
    if guess == the_number:
        print("You win! The number was", the_number)
        print("And it only took you", tries, "tries!\n")

Answer 1

跟踪猜测的数字，只有在用户没有猜到我们猜测的数字中已有数字时才会增加：

import random

print("Guess a number between 1-100")

the_number = random.randint(1, 100)
tries = 0
# store all the user guesses
guessed = set()

while True:
    guess = int(input("Guess a number: "))
    # if the guess is in our guesses set, the user has guessed before
    if guess in guessed:
        print("You already guessed that number!")
        continue
    # will only increment for unique guessed
    tries += 1
    if guess == the_number:
        print("You win! The number was", the_number)
        print("And it only took you", tries, "tries!\n")
        break
    elif guess > the_number:
        print("Lower")
    # if it's not == or >, it has to be <
    else:
        print("Higher")
    # add guess each time
    guessed.add(guess)

你也有一些关于你的排序的逻辑，比如在循环外猜测，这可能意味着如果用户第一次猜到你就没有进入循环。

Answer 2

这就是你应该如何编写代码。

UDPClient