Question

在Oracle中，仅使用ORDER BY不会对版本号进行排序。我的Version_Number字段被声明为VARCHAR，我无法更改它。例如：以下版本：

应按

排序

我已经研究了几个帖子但是它们似乎都没有真正服务于我的目的，或者答案是针对SQL Server等而不是Oracle。我遇到了这个看起来很有用的特殊sql。

select version_number from mytable 
order by lpad(version_number, 4) desc;

以这种方式对版本进行排序：

我相信这个sql语句适用于SQL Server：

select version_number from mytable 
order by cast ('/' + replace(version_number , '.', '/') + '/' as hierarchyid) desc;

但是，这不适用于Oracle。 Oracle中是否有hierarchyid的替代方案？

是否有人能够提出SQL来准确地对这些版本进行排序？

我已经看到了下面提到的帖子（链接附件）。所以请不要告诉我这篇文章是重复的。
SQL sort by version "number", a string of varying length
How Can I Sort A 'Version Number' Column Generically Using a SQL Server Query
Version number sorting in Sql Server
mysql sorting of version numbers
还有更多。

Answer 1

这是一种方法。首先按.之前的数字排序，然后按.

之后的数字排序

select version_number 
from mytable 
order by substr(version_number, 1, instr(version_number,'.')-1) desc
        ,length(substr(version_number, instr(version_number,'.')+1)) desc
        ,substr(version_number, instr(version_number,'.')+1) desc

Answer 2

此SQL支持您的输入数据以及任何包含的修订版或构建数字。

with 
   inputs as (select '1.20'         as version_number from dual union all  
              select '1.9'          as version_number from dual union all
              select '1.18'         as version_number from dual union all
              select '1.13'         as version_number from dual union all
              select '1.5'          as version_number from dual union all
              select '1.11'         as version_number from dual union all
              select '2.0'          as version_number from dual union all
              select '1.8'          as version_number from dual union all
              select '1.3'          as version_number from dual union all
              select '1.2'          as version_number from dual union all
              select '1.1'          as version_number from dual union all
              select '1.0'          as version_number from dual union all
              select '1.10'         as version_number from dual union all
              select ' 3.1 '        as version_number from dual union all
              select '3.1.1000'     as version_number from dual union all
              select '3.1.1'        as version_number from dual union all
              select '3.1.100'      as version_number from dual union all
              select '3.1.2.1000'   as version_number from dual union all
              select '3.1.2.1'      as version_number from dual union all
              select '3.1.2.100 '   as version_number from dual)
,versions as  (select  trim(version_number) as version_number,
        nvl(LPAD(trim(regexp_substr(version_number, '[^.]+', 1, 1)),5,'0'),'00000') AS Major,
        nvl(LPAD(trim(regexp_substr(version_number, '[^.]+', 1, 2)),5,'0'),'00000') AS Minor, 
        nvl(LPAD(trim(regexp_substr(version_number, '[^.]+', 1, 3)),5,'0'),'00000') AS Revision, 
        nvl(LPAD(trim(regexp_substr(version_number, '[^.]+', 1, 4)),5,'0'),'00000') AS Build 
        from inputs 
        ORDER BY Major desc, Minor desc, Revision desc, Build desc)
--select * from versions; 
select version_number from versions;

删除 - 以查看中间结果。

对于OP，将“input as（select ... from dual）”替换为：

   inputs as (select version_number from mytable)

Answer 3

正如Joel Coehoorn建议here，＆＃34;重构版本号存储，以便每个部分都有自己的列：MajorVersion，MinorVersion，Revision，Build＆＃34;。

我重新发帖，因为我发现非常非常有帮助！

要扩展，我希望获得MAX版本号，最后使用此脚本以及Joel的建议。

    -- GET MAX VERSION NUMBER
    SELECT
        REPLACE(vnum, ' ', '') AS versionum
    FROM
        (SELECT
            MAX(LPAD(major, 4) || '.' || LPAD(minor, 4) || '.' || LPAD(revision, 4)) AS vnum
        FROM
            my_table
        ORDER BY
            major
          , minor
          , revision
        ) tbl1

Oracle SQL对版本号进行排序

3 个答案: