使用delete属性而不影响父对象

Question

以下是两个名为primary和secondary的对象：

var primary = {"gonna":3,"lol":114,"wouldn":2,"know":6,"lowkey":2,"man":5};
var secondary = primary;

当我使用delete secondary['lol'];时，它会从两个对象中删除该属性：jsfiddle

我的问题是：如何从secondary删除属性而不将其从primary删除？

Answer 1

secondary引用与primary相同的对象。如果要将它们分开，则需要创建primary的副本。

有像Lodash这样的库，它们具有允许您克隆对象的实用程序功能（下面的示例），但是there are other ways too。

var primary = {"gonna":3,"lol":114,"wouldn":2,"know":6,"lowkey":2,"man":5};
var secondary = _.clone(primary);

delete secondary.lol;

document.write(JSON.stringify(primary));
document.write('<br>');
document.write(JSON.stringify(secondary));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/3.10.1/lodash.js"></script>

Answer 2

创建小提琴意味着创建工作小提琴，而不仅仅是粘贴代码

http://jsfiddle.net/Lso7kwLs/

克隆对象可以帮到你。例如：

$D$9

Answer 3

你应该尝试：

var primary = {"gonna":3,"lol":114,"wouldn":2,"know":6,"lowkey":2,"man":5}; var secondary = $.extend({}, primary); delete secondary['lol'];