Question

我设置的搜索会返回我想要的结果，但是当搜索结果返回的次数超过我的答案时，我无法让它们显示在多行中。我尝试使用一个简单的中断在每次返回后开始一个新行，但它不起作用。任何帮助将不胜感激。

<?php

$servername = "localhost";
$username = "xxx";
$password = "xxx";
$dbname = "oldga740_SeniorProject";


// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
     die("Connection failed: " . $conn->connect_error);
}


// If there is a search variable try to search database
if(isset($_POST['search'])) {
    $searchq = $_POST['search'];
    $searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
    $sql = "SELECT * FROM Customers WHERE Client LIKE '%$searchq%'";

        if ($result = mysqli_query($conn, $sql)) {

    /* fetch associative array */
    while ($row = mysqli_fetch_row($result)) {
        printf ("%s (%s)\n", $row[0], $row[1]);
    }

    /* free result set */
    mysqli_free_result($result);
}

/* close connection */
mysqli_close($conn);
}






?>

<html>

<head>

</head>

<body>

<form action="Index.php" method="post">
  <input type="text" name="search" placeholder="Search...." />
  <input type="submit" value=">>" />
</form>



</body>

</html>

Answer 1

使用＆lt; br＆gt;而不是简单的换行。

printf ("%s (%s)<br/>", $row[0], $row[1]);

如何让我的搜索结果显示超过I行的多个回报？

1 个答案: