我在网上找到了这个代码并进行了测试。它工作但它进入无限循环。我看到一些关于为页面索引创建新func
的帖子。
链接到我找到代码的网站:http://samwize.com/2015/10/13/how-to-create-uipageviewcontroller-in-storyboard-in-container-view/
是否有人愿意编辑代码以便循环结束?
import UIKit
class MyPageViewController: UIPageViewController, UIPageViewControllerDataSource, UIPageViewControllerDelegate {
var pages = [UIViewController]()
override func viewDidLoad() {
super.viewDidLoad()
self.delegate = self
self.dataSource = self
let page1: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page1")
let page2: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page2")
let page3: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page3")
pages.append(page1)
pages.append(page2)
pages.append(page3)
setViewControllers([page2], direction: UIPageViewControllerNavigationDirection.Forward, animated: false, completion: nil)
}
func pageViewController(pageViewController: UIPageViewController, viewControllerBeforeViewController viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.indexOf(viewController)!
let previousIndex = abs((currentIndex - 1) % pages.count)
return pages[previousIndex]
}
func pageViewController(pageViewController: UIPageViewController, viewControllerAfterViewController viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.indexOf(viewController)!
let nextIndex = abs((currentIndex + 1) % pages.count)
return pages[nextIndex]
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}
答案 0 :(得分:8)
页面视图控制器不应该换行。
您的viewControllerBeforeViewController
和viewControllerAfterViewController
方法都是从第一个到最后一个或最后一个到第一个来写的,这是错误的。
只需将viewControllerBeforeViewController
重写为递减currentIndex
,并返回该视图控制器,除非它<0。如果它<0,则返回nil。
同样适用于viewControllerAfterViewController
,增加currentIndex
,如果是< pages.count
,则返回该项,否则为无。
看看你是否可以编写该代码。
答案 1 :(得分:3)
var pages = [UIViewController]()
extension ViewController: UIPageViewControllerDataSource {
func pageViewController(_ pageViewController: UIPageViewController,
viewControllerBefore viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.index(of: viewController)!
let previousIndex = currentIndex - 1
return (previousIndex == -1) ? nil : pages[previousIndex]
}
func pageViewController(_ pageViewController: UIPageViewController,
viewControllerAfter viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.index(of: viewController)!
let nextIndex = currentIndex + 1
return (nextIndex == pages.count) ? nil : pages[nextIndex]
}
}
答案 2 :(得分:-1)
import UIKit
类MyPageViewController:UIPageViewController,UIPageViewControllerDataSource,UIPageViewControllerDelegate {
var pages = [UIViewController]()
override func viewDidLoad() {
super.viewDidLoad()
self.delegate = self
self.dataSource = self
let page1: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page1")
let page2: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page2")
let page3: UIViewController! = storyboard?.instantiateViewControllerWithIdentifier("page3")
pages.append(page1)
pages.append(page2)
pages.append(page3)
setViewControllers([page2], direction: UIPageViewControllerNavigationDirection.Forward, animated: false, completion: nil)
}
func pageViewController(pageViewController: UIPageViewController, viewControllerBeforeViewController viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.indexOf(viewController)!
let previousIndex = abs((currentIndex - 1) % pages.count)
if (previousIndex > 0)
{
return nil
}
return pages[previousIndex]
}
func pageViewController(pageViewController: UIPageViewController, viewControllerAfterViewController viewController: UIViewController) -> UIViewController? {
let currentIndex = pages.indexOf(viewController)!
let nextIndex = abs((currentIndex + 1) % pages.count)
if (nextIndex < 1)
{
return nil
}
return pages[nextIndex]
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
}