Question

我有一个$accounts数组，其中包含此数据

array:2 [▼
  0 => array:25 [▼
    "email_address" => "bob@xyzcorp.com"
    "account_id" => 111
    "password" => "abc"
    "account_type" => "admin"
    "name_prefix" => "Mr"
    "first_name" => "Bob"
    "middle_names" => "X."
    "last_name" => "Jones"
    "name_suffix" => "Jr."
    "non_person_name" => false
    "DBA" => ""
    "display_name" => "BobJ"
    "address1" => "111 Park Ave"
    "address2" => "Floor 4"
    "address3" => "Suite 4011"
    "city" => "New York"
    "state" => "NY"
    "postal_code" => "10022"
    "nation_code" => "USA"
    "phone1" => "212-555-1212"
    "phone2" => ""
    "phone3" => ""
    "time_zone_offset_from_utc" => -5
    "customer_type" => 2
    "last_updated_utc_in_secs" => 200200300
  ]
  1 => array:25 [▼
    "email_address" => "tom@xyzcorp.com"
    "account_id" => 112
    "password" => "abd"
    "account_type" => "mbn"
    "name_prefix" => "Mr"
    "first_name" => "Tom"
    "middle_names" => "Z."
    "last_name" => "Smith"
    "name_suffix" => "Sr."
    "non_person_name" => false
    "DBA" => ""
    "display_name" => "TomS"
    "address1" => "112 Park Ave"
    "address2" => "Floor 3"
    "address3" => "Suite 3011"
    "city" => "New York"
    "state" => "NY"
    "postal_code" => "10022"
    "nation_code" => "USA"
    "phone1" => "212-555-2323"
    "phone2" => ""
    "phone3" => ""
    "time_zone_offset_from_utc" => -5
    "customer_type" => 2
    "last_updated_utc_in_secs" => 200200300
  ]
]

我想从这个数组中构造一个新数组。但新阵列我只想拥有2个键：email_address和password。

我试过了：

$new_array = array();
$i = 0;
foreach ($accounts as $account) {

  $new_array[$i++];

  foreach ($account as $user) {
    $new_array['email_address'] = $user['email_address'];
    $new_array['password'] = $user['password'];
  }
}

dd($new_array);

我希望有人能在这里给我一点推动。

Answer 1

您没有向$new_array添加新元素。每次通过foreach循环，您都会覆盖相同的两个键。 $new_array的元素应该是数组。

您也不需要内部循环，因为每个帐户只是一个用户。

foreach ($accounts as $account) {
    $new_array[] = array('email_address' => $account['email_address'],
                         'password' => $account['password']);
}

您不需要变量$i，因为$new_array[] =会将新元素推送到数组上。

Answer 2

 $new_array[$i++];

  foreach ($account as $user) {
    $new_array['email_address'] = $user['email_address'];
    $new_array['password'] = $user['password'];
  }

您的问题就在这里，您几乎拥有它，但是当您在数组中使用数组时，使用两组foreach循环，您需要具有相同的如果要保留多个记录“password和email_address。

，请使用结构深度
所以，用以下内容替换上面的引用：

$i++ $new_array[$i]; foreach ($account as $user) { $new_array[$i]['email_address'] = $user['email_address']; $new_array[$i]['password'] = $user['password']; }

这将输出

$new_array( [0] ===> ['password'] --> {data} ===> ['email_address'] --> {data} [1] ===> ['password'] --> {data} ===> ['email_address'] --> {data} .... )

修改这可以进一步减少和整理为：

$i++ $new_array[$i]; $new_array[$i]['email_address'] = $account['email_address']; $new_array[$i]['password'] = $account['password'];

因为你知道你想要的值的键，所以你不需要分开外部数组来找到任何东西，你可以直接引用 outerValue （{{1} }）然后键（account等）。

在PHP中用现有数组构造一个新数组

2 个答案: