PHP子句使用Where子句排序

Question

我需要在ASC订单中按ORDER BY number字段，但它无效。

$sThree = "SELECT `id`, `name`, `number`, `logo` FROM `itv` WHERE `id` = {$rTwoArray['service_id']} ORDER BY `number` ASC";
$qThree = mysql_query($sThree, $conn1);
$rThree[] = mysql_fetch_assoc($qThree);

无法弄清楚，请帮我调试。

Answer 1

上面显示的查询不同，结果图像也不同。您已使用WHERE id = {something}它应该在结果中提供所有相同的id。请附上正确的结果。

您在此处获得的查询结果可能来自另一个查询，这就是您无法获得有序结果的原因。

每当代码行为不自然时，首先要看代码是在循环中工作还是从不假设。

Answer 2

使用MySQL CAST(expression AS TYPE)

order by CAST(number AS SIGNED) ASC

尝试此MySQL查询

$sThree = "SELECT `id`, `name`, `number`, `logo` FROM `itv` 
WHERE `id` = {$rTwoArray['service_id']} order by CAST(number AS SIGNED) ASC";

Answer 3

由于查询是在循环中，我对最终数组进行了排序。

    $sThree = "SELECT `id`, `name`, `number`, `logo` FROM `itv` WHERE `id` = {$rTwoArray['service_id']}";
    $qThree = mysql_query($sThree, $conn1);
    $rThree[] = mysql_fetch_assoc($qThree);

usort($rThree, function ($item1, $item2) {
    return $item1['number'] >= $item2['number'];
});
debug($rThree);