信件柜台代码

时间:2015-10-13 22:23:05

标签: java loops counter letter

//提示符是:编写一个程序,要求用户输入一个字符串,然后//然后要求用户输入一个字符。程序应计算并显示//指定字符在字符串中出现的次数。

import java.util.Scanner;
public class LetterCounter{
Scanner keyboard = new Scanner (System.in);     //Scanner
// Declare Variables
    String userString;      // String user entered
    String userCharacter;   // Character user entered
    int StringSize;      
// Ask the user to enter a string
    System.out.println("Please Enter a String.");
    userString = keyboard.nextLine();

// Ask the user to enter a charcter
    System.out.println("Please Enter a Character.");
    userCharacter = keyboard.nextLine();

// Count and display the number of times that character appears in the
// string chosen by the user.
    int character; 
    character = Integer.parseInt(userCharacter);
    StringSize = userString.charAt(character);
}
}

出于某种原因,我无法让它工作,我只是不知道从哪里开始。我可能需要一个FOR-LOOP吗?

感谢您的帮助

2 个答案:

答案 0 :(得分:1)

嗨看看这个

package gmit;

import java.util.Scanner;
public class LetterCounter{

    public static void main(String[] args) {
        String keyBoardChar;    

Scanner keyboard = new Scanner (System.in);     //Scanner
// Declare Variables
    String userString;      // String user entered
    char userCharacter;   // Character user entered
    int StringSize;      
// Ask the user to enter a string
    System.out.println("Please enter a string");
    userString = keyboard.nextLine();

// Ask the user to enter a charcter

    System.out.println("Please Enter a Character.");
    char kChar = keyboard.next().charAt(0);

// Count and display the number of times that character appears in the
// string chosen by the user.
    int character = 0; 
    //character = Integer.parseInt(userCharacter);
    //StringSize = userString.charAt(character);

    char[] StringToChar = userString.toCharArray();
    for(int i = 0; i < StringToChar.length - 1; i++){
        if ( StringToChar[i] == kChar){
            character++;
        }
    }
    System.out.println("character count is " + character);

} }

我选择了这封信 char kChar = keyboard.next()。charAt(0);

并将String转换为Char数组,运行for循环遍历每个字母并检查它是否与所选字符相同。每次检查结果为真,我都会在字符计数器中添加一个。

答案 1 :(得分:0)

是的,你需要使用for循环。

int count = 0;
for (char ch: userString.toCharArray()) {
    if(userChar == ch) count++;
}