数据如下所示
x = [1,2,3,4,5,6]
y = [1.2,1.2,-2.1,-2.1,4.1,-4.1] #these y值总是成对的,这样我需要一条实线来连接这些等价值,然后在这对之间用虚线表示下一对。
答案 0 :(得分:3)
你的意思是这样吗?
import pylab
xdata = [0, 1, 2, 3, 4, 5]
ydata = [0, 1, 2, 2, 1, 0]
# Assuming xdata, ydata are of suitable length and type
plots = [pylab.plot(xdata[i:i + 2], ydata[i:i + 2], **whatever_keyword_arguments) for i in xrange(0, len(xdata), 2)]
pylab.show()
OP编辑后编辑:
我明白你的意思了,用破折号添加线条是微不足道的。
def plot_broken(xseq, yseq, even=True, **plot_kwargs):
size = len(xseq)
assert size == len(yseq)
assert size % 2 == 0
start = 0 if even else 1
return [pylab.plot(xseq[i:i + 2], yseq[i:i + 2], **plot_kwargs)
for i in xrange(start, size, 2)]
plots = plot_broken(xdata, ydata, even=True, color="m",
linestyle="solid")
plots += plot_broken(xdata, ydata, even=False, color="m",
linestyle="dashed")
答案 1 :(得分:3)
这是否达到了你所希望的目标?
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<html>
<body>
<div align="center">
<form:form modelAttribute="profilePic" method="POST"enctype="multipart/form-data" action="/SpringMvc/addImage">
<input type="file" name="fileUpload" id="file" size="50" />
<input type="submit" value="Add Picture" onClick="Validate();"/>
</form:form>
</div>
<script>
function Validate(){
var image =document.getElementById("file").value;
if(image!=''){
var checkimg = image.toLowerCase();
if (!checkimg.match(/(\.jpg|\.png|\.JPG|\.PNG|\.gif|\.GIF|\.jpeg|\.JPEG)$/)){
alert("Please enter Image File Extensions .jpg,.png,.jpeg,.gif");
document.getElementById("file").focus();
return false;
}
}
return true;
}
</script>
</body>
</html>