大家好我想在Spring + Mysql中返回带有rest http请求的userName。
控制器:
scrolledToPosition = false;
型号:
@Controller
@SessionAttributes("user")
public class UserController {
@Autowired
private UserService userService;
@RequestMapping(method=RequestMethod.GET, value="/userss/{userName}")
public @ResponseBody String getUserName(@PathVariable String userName) {
return userName;
}
}
我只想检索我的服务放置,删除,发布和获取请求映射连接我的模型到我的mysql数据库。我试图以这种方式提出请求: http://localhost:8080/portuzona/userss?userName=Arnoldo
但我明白了:
@Entity
@Table(name="users")
public class User {
@Id
@GeneratedValue
private Long id;
@NotEmpty
@Size(min=4, max=20)
private String userName;
@NotEmpty
private String firstName;
@NotEmpty
private String lastName;
@NotEmpty
@Size(min=4, max=8)
private String password;
@NotEmpty
private String status;
@NotEmpty
@Email
private String emailAddress;
@NotNull
@Past
@DateTimeFormat(pattern="MM/dd/yyyy")
private Date dateOfBirth;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public String getStatus() {
return status;
}
public void setStatus(String status) {
this.status = status;
}
public String getEmailAddress() {
return emailAddress;
}
public void setEmailAddress(String emailAddress) {
this.emailAddress = emailAddress;
}
public Date getDateOfBirth() {
return dateOfBirth;
}
public void setDateOfBirth(Date dateOfBirth) {
this.dateOfBirth = dateOfBirth;
}
}
portuzona和用户被正确处理(html视图),但我无法进入我的控制器。
Log正确地说bean已经找到了表:
HTTP Status 404 - /portuzona/userss
type Status report
message /portuzona/userss
description The requested resource is not available.
正如用户在此处所要求的更多信息可以提供帮助..或者不是:
/WEB-INF/servlet.xml
sep 25, 2015 2:07:22 PM org.hibernate.tool.hbm2ddl.TableMetadata <init>
INFO: HHH000261: Table found: portuzona.users
sep 25, 2015 2:07:22 PM org.hibernate.tool.hbm2ddl.TableMetadata <init>
INFO: HHH000037: Columns: [dateofbirth, password, firstname, emailaddress, id, username, lastname, status]
/WEB-INF/config/servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>usersHibernateServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/config/servletConfig.xml</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>usersHibernateServlet</servlet-name>
<url-pattern>*.html</url-pattern>
</servlet-mapping>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/jpaContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<display-name>Archetype Created Web Application</display-name>
</web-app>
答案 0 :(得分:1)
看起来你正在混合映射和路径变量。两个选项:
1:
@RequestMapping(method=RequestMethod.GET, value="/userss/{userName}")
public @ResponseBody String getUname(@PathVariable String userName) {
return userName;
}
http://localhost:8080/portuzona/userss/Arnoldo
2:
@RequestMapping(method=RequestMethod.GET, value="/userss/yourmapping")
public @ResponseBody String getUserName(@RequestParam String username) {
return username;
}
http://localhost:8080/portuzona/userss/yourmapping?username=Arnoldo
答案 1 :(得分:0)
使用http://localhost:8080/portuzona/userss?userName=Arnoldo
尝试以下操作 Dim Db As Database, tDef As TableDef
Set Db = CurrentDb
Set tDef = Db.CreateTableDef("ARCH_CALL")
tDef.Connect = BuildLinkString(UserName)
tDef.SourceTableName = CreateDataSourceString(BuildDataSourceString, "LinkedTableName")
Db.TableDefs.Append tDef