我正在尝试运行以下代码。但是它显示了下标超出范围的错误。当我尝试调试时,它在5行中显示错误:范围(“A1”)。选择 在调试时,当我将第4行的Sheet1作为Sheet2时,它不会在Sheet2上进行。 请帮我正确运行代码。
Sub excelmacro()
Application.ScreenUpdating = False
Sheets(“Sheet1”).Select
Range(“A1”).Select
Sheets(“Sheet2”).Select
Range(“A2”).Select
For i = 1 To 3
Sheets(“Sheet1”).Select
If Len(ActiveCell.Value) > 1 Then
Sheets(“Sheet1”).Select
Xname = Right(ActiveCell.Value, Len(ActiveCell.Value) - 6)
Xdesig = Right(ActiveCell.Offset(1, 0).Value, Len(ActiveCell.Offset(1, 0).Value) - 13)
Xsalary = Right(ActiveCell.Offset(2, 0).Value, Len(ActiveCell.Offset(2, 0).Value) - 8)
Sheets(“Sheet2”).Select
ActiveCell.Value = Xname
ActiveCell.Offset(0, 1).Value = Xdesig
ActiveCell.Offset(0, 2).Value = Xsalary
ActiveCell.Offset(1, 0).Select
Sheets(“Sheet1”).Select
ActiveCell.Offset(3, 0).Select
Else
i = 10
End If
i = i - 1
Next
Application.ScreenUpdating = True
End Sub
答案 0 :(得分:0)
引号是奇怪的并且会产生错误,但即使在更改为“正常”之后,也会出现下标范围错误:
不要使用Sheets
,请尝试Worksheets
:
Worksheets("Sheet1").Select
答案 1 :(得分:0)
总结我的评论:
原始代码中的双引号格式奇怪。使用记事本或VBA IDE将它们替换为适当的纯文本双引号。
如果启用Option Explicit
,请务必在使用变量前声明变量。即使它没有开启,也是一个很好的做法。
(今晚我有更多时间时要更新)避免选择并使用ActiveCell
/ ActiveSheet
引用。
对代码进行细微更改后,它应如下所示:
Sub excelmacro()
Dim i As Double, _
Xname As String, _
Xdesig As String, _
Xsalary As String
Application.ScreenUpdating = False
Sheets("Sheet1").Select
Range("A1").Select
Sheets("Sheet2").Select
Range("A2").Select
For i = 1 To 3
Sheets("Sheet1").Select
If Len(ActiveCell.Value) > 1 Then
Sheets("Sheet1").Select
Xname = Right(ActiveCell.Value, Len(ActiveCell.Value) - 6)
Xdesig = Right(ActiveCell.Offset(1, 0).Value, Len(ActiveCell.Offset(1, 0).Value) - 13)
Xsalary = Right(ActiveCell.Offset(2, 0).Value, Len(ActiveCell.Offset(2, 0).Value) - 8)
Sheets("Sheet2").Select
ActiveCell.Value = Xname
ActiveCell.Offset(0, 1).Value = Xdesig
ActiveCell.Offset(0, 2).Value = Xsalary
ActiveCell.Offset(1, 0).Select
Sheets("Sheet1").Select
ActiveCell.Offset(3, 0).Select
Else
i = 10
End If
i = i - 1
Next
Application.ScreenUpdating = True
End Sub
答案 2 :(得分:0)
我认为这就是你要做的事情:
Sub excelmacro()
Dim lastrowinSheet1 As Long
Dim cellinSheet2 As Range
Dim rCell As Range
Dim x As Long
With ThisWorkbook
'Set a reference to cell A1 on Sheet2.
Set cellinSheet2 = .Worksheets("Sheet2").Range("A1")
With .Worksheets("Sheet1")
'This will return the last row number containing data in column A.
lastrowinSheet1 = .Cells(Rows.Count, 1).End(xlUp).Row
'Now loop through each cell in column A of sheet1.
For x = 1 To lastrowinSheet1
If Len(.Cells(x, 1)) > 1 Then
cellinSheet2.Value = Right(.Cells(x, 1).Value, Len(.Cells(x, 1).Value) - 6)
cellinSheet2.Offset(, 1) = Right(.Cells(x, 1).Offset(1).Value, Len(.Cells(x, 1).Offset(1).Value) - 13)
cellinSheet2.Offset(, 2) = Right(.Cells(x, 1).Offset(2).Value, Len(.Cells(x, 1).Offset(2).Value) - 8)
Set cellinSheet2 = cellinSheet2.Offset(1)
x = x + 2
End If
Next x
End With
End With
End Sub
我试图拆开你的代码 - 我认为这就是它正在做的事情:
Sub excelmacro1()
'Stop the screen flicker.
Application.ScreenUpdating = False
'Select cell A1 on Sheet1.
Sheets(“Sheet1”).Select
Range(“A1”).Select
'Select cell A2 on sheet 2.
Sheets(“Sheet2”).Select
Range(“A2”).Select
For i = 1 To 3
'Select Sheet1 again.
Sheets(“Sheet1”).Select
'If the length of text in the ActiveCell is greater than 1 character then
'execute the lines up to ELSE.
If Len(ActiveCell.Value) > 1 Then
'Select Sheet1 yet again.
Sheets(“Sheet1”).Select
'Hope the value in the ActiveCell isn't longer than 6 digits, or it will error out.
'Take all characters from the ActiveCell except the last 6.
Xname = Right(ActiveCell.Value, Len(ActiveCell.Value) - 6)
'Take all characters from the ActiveCell except the last 13.
Xdesig = Right(ActiveCell.Offset(1, 0).Value, Len(ActiveCell.Offset(1, 0).Value) - 13)
'Take all characters from the ActiveCell except the last 8.
Xsalary = Right(ActiveCell.Offset(2, 0).Value, Len(ActiveCell.Offset(2, 0).Value) - 8)
'Select Sheet2.
Sheets(“Sheet2”).Select
'Place the values in ActiveCell and the two columns to the right.
ActiveCell.Value = Xname
ActiveCell.Offset(0, 1).Value = Xdesig
ActiveCell.Offset(0, 2).Value = Xsalary
'Select the next row down.
ActiveCell.Offset(1, 0).Select
'Active Sheet1 again.
Sheets(“Sheet1”).Select
'Select the cell 3 rows down from the previous row.
ActiveCell.Offset(3, 0).Select
Else
'If the lengh of text in the ActiveCell is 1 character or less then set the value of i to 10.
i = 10
End If
'Remove 1 from i.
i = i - 1
Next
Application.ScreenUpdating = True
End Sub