所以我需要将一个整数数组打印到一个String中,我几乎没有问题
public static String arrayToString(int[] anArray) {
String x = "";
String y = "";
String result = "";
for (int i = 0; i < anArray.length; i++) {
y = Integer.toString(anArray[i]);
x = x + ", " + y;
}
result = "[" + x + "]";
return result;
}
public static void main(String[] args) {
int arrayInt[] = new int[] { 80, 100, 80, 92, 95, 87, 82, 76, 45, 76, 80, 70};
System.out.println("array : " + arrayToString(arrayInt));
}
当我执行代码时,而不是打印:
[80,100,80,92,95,87,82,76,45,76,80,70]
我明白了:
[,80,100,80,92,95,87,82,76,45,76,80,70]
这应该对我来说非常简单,但是我被卡住了,我需要在哪里删除异常?
答案 0 :(得分:0)
您只是在开头添加额外的,
。摆脱它的一个简单方法是,
取代
result = "[" + x + "]";
带
result = "[" + x.substring(1) + "]";
但最好的解决方案是使用Arrays.toString
。有关详细信息,请参阅this。
答案 1 :(得分:0)
问题在于您在开头时收到了额外逗号 ,
。这将解决您在arrayToString
函数中的问题:
public static String arrayToString(int[] anArray) {
String x = "";
String y = "";
String result = "";
for (int i = 0; i < anArray.length-1; i++) {
y = Integer.toString(anArray[i]);
x = x + y + ",";
}
y = Integer.toString(anArray[anArray.length-1]);
x = x + y;
result = "[" + x + "]";
return result;
}
答案 2 :(得分:0)
public static String arrayToString(int[] anArray) {
String x = "";
String y = "";
String result = "";
for (int i = 0; i < anArray.length; i++) {
y = Integer.toString(anArray[i]);
if(x.isEmpty()){
x = y;
} else {
x = x + ", " + y;
}
}
result = "[" + x + "]";
return result;
}
public static void main(String[] args) {
int arrayInt[] = new int[] { 80, 100, 80, 92, 95, 87, 82, 76, 45, 76, 80, 70 };
System.out.println("array : " + arrayToString(arrayInt));
}
答案 3 :(得分:0)
您可以检查第一个元素。
if( i == 0 )
x = y;
else
x = x + ", " + y;
答案 4 :(得分:-1)
请更改代码中的最后一行,结果字符串变量如下:
public static String arrayToString(int[] anArray) {
String x = "";
String y = "";
String result = "";
for (int i = 0; i < anArray.length; i++) {
y = Integer.toString(anArray[i]);
x = x + ", " + y;
}
result = "[" + x + "]";
return result.charAt(0)+result.substring(3);
}