Question

此代码应该有效。为什么不呢？

<!DOCTYPE html>
<body>

<h1> The "^" operator in Javascript </h1>

<p id = "foo"></p>

<script>

function f(){
//vars
var a = 5;
var b = 13;
var c = a ^ b;
var binA = a.toString(2);
var binB = b.toString(2);
var binC = c.toString(2);
var strA = a.toString();
var strB = b.toString();
var strC = c.toString();

//make output string
var lineA = "a = " + strA + " = " binA + ", ";
var lineB = "b = " + strB + " = " binB + ", ";
var lineC = "c = " + strC + " = " binC + ", ";
var outputStr = lineA + lineB + lineC;

//output
document.getElementById("foo").innerHTML = outputStr;

}

f();

// For some reason this shows the contents of the header only

</script>
</body>

我在a，b和c上进行了toString（）转换，因为我无法理解为什么输出无法在Google Chrome中显示。我认识到他们不应该是必要的。但我想让代码尽可能地变成犹太人。我已将字符串连接为子字符串，因为在此代码的前一次迭代中，注释掉了＆＃39; C＆＃39;字符串连接部分允许＆＃39; A＆＃39;和＆＃39; B＆＃39;要显示的输出字符串的相关部分。此外，它保持视觉格式规则，我试图用来进行错误检查。

Answer 1

更新了代码，您错过了'+'

See this fiddle

var lineA = "a = " + strA + " = " + binA + ", ";
var lineB = "b = " + strB + " = " + binB + ", ";
var lineC = "c = " + strC + " = " + binC + ", ";
var outputStr = lineA + lineB + lineC;

Answer 2

语法错误，你在binA，binB和binC之前错过了'+'

var lineA = "a = " + strA + " = " + binA + ", ";
var lineB = "b = " + strB + " = " + binB + ", ";
var lineC = "c = " + strC + " = " + binC + ", ";
var outputStr = lineA + lineB + lineC;

当我在ff和chrome

中修复该错误时，输出打印如下

a = 5 = 101, b = 13 = 1101, c = 8 = 1000,

Answer 3

这是因为你在第24,25和26行的+，binA和binB之前错过了binC标记:)你有一些无效的javascript ，它在控制台中抛出错误。

Answer 4

您在javascript中出现语法错误。用

替换输出字符串块

//make output string
var lineA = "a = " + strA + " = "+ binA + ", ";
var lineB = "b = " + strB + " = "+ binB + ", ";
var lineC = "c = " + strC + " = "+ binC + ", ";
var outputStr = lineA + lineB + lineC;

它适合你。感谢

为什么用javascript这个简单的.html文件不起作用？

4 个答案: