Question

我正在SQL中创建一个数据透视表。我想让IsNull(ItemQty, 0)工作。我有下面代码的方式不会起作用，因为它会抛出以下错误。如果我将顶部的Select语句更改为Select * from（），它将起作用。但是，那并不允许我做IsNull。

ShipWeekMod和ItemQty是vtc_ItemForecastSummary视图中CASE语句的结果。有什么想法吗？

消息207，级别16，状态1，行16无效的列名称＆＃39; ShipWeekMod＆＃39;。消息207，级别16，状态1，行16无效的列名称＆＃39; ItemQty＆＃39;。

select
OfferTypeShipYear, EDPNO, OfferType, ShipYear, ShipWeekMod, IsNull(ItemQty, 0) as ItemQty
from
(
select OfferTypeShipYear, EDPNO, OfferType, ShipYear, ShipWeekMod, ItemQty as ItemQty from vtc_ItemForecastSummary
) DataTable
PIVOT
(
  SUM(ItemQty)
  FOR ShipWeekMod
  IN (
    [2],[4],[6],[8],[10],[12],[14],[16],[18],[20],[22],[24], [26],[28],[30],[32],[34],[36],[38],[40],[42],[44],[46],[48],[50],[52] 
  )
) PivotTable

Answer 1

您无法在select中重复使用您转动的列。相反，您必须将isnull函数应用于pivot返回的每个列。由于这可能很繁琐，您可以考虑重写查询以使用动态sql。

应该看起来像这样：

select 
    OfferTypeShipYear, EDPNO, OfferType, ShipYear,
    isnull([2],0) as [2],
    isnull([4],0) as [4],
    isnull([6],0) as [6],
    isnull([8],0) as [8]
    ... etcetera

from (
    select 
       OfferTypeShipYear, EDPNO, OfferType, 
       ShipYear, ShipWeekMod, ItemQty 
    from vtc_ItemForecastSummary
) DataTable
PIVOT (
  SUM(ItemQty)
  FOR ShipWeekMod
  IN (
    [2],[4],[6],[8],[10],[12],[14],[16],[18],[20],[22],[24], 
    [26],[28],[30],[32],[34],[36],[38],[40],[42],[44],[46],[48],[50],[52] 
  )
) PivotTable

为什么我在数据透视表中获得无效的列名称

1 个答案: