Lets say I have a database containing the following rows:
id (auto_incremented) | id_person | first_name | last_name | phone | email
-----------------------------------------------------------------------------
1 | 12 | kevin | smith | | kevin@hotmail.com
2 | 12 | kevin | smith | 1-800-123-4567 |
3 | 33 | joe | jones | 1-800-765-4321 |
4 | 33 | joe | thompson | | joe@hotmail.com
5 | 33 | joe | thompson | | newjoe@hotmail.com
Based on id_person
, I want to output the following in a single query:
id | id_person | first_name | last_name | phone | email
-----------------------------------------------------------------------------
2 | 12 | kevin | smith | 1-800-123-4567 | kevin@hotmail.com
5 | 33 | joe | thompson | 1-800-765-4321 | newjoe@hotmail.com
So basically, I just want to take the newest row values, and if they are empty, grab the values from the first row which isn't empty.
How do I do this? Hope this makes sense.
答案 0 :(得分:0)
SELECT id_person, subQ.lastID
, GROUP_CONCAT(IF(subQ.lastFieldXId = tblFields.ID, tblFields.fieldX, NULL)) AS fieldX
, GROUP_CONCAT(IF(subQ.lastFieldYId = tblFields.ID, tblFields.fieldY, NULL)) AS fieldY
[, ...]
FROM
(SELECT id_person
, MAX(id) AS lastID
, MAX(IF(IFNULL(fieldX, '') = '', 0, id) AS lastFieldXId
, MAX(IF(IFNULL(fieldY, '') = '', 0, id) AS lastFieldYId
[, ....]
FROM theTable
GROUP BY id_person) AS subQ
LEFT JOIN theTable AS tblFields USING (id_person)
;
The LEFT JOIN may or may not be faster as
LEFT JOIN theTable AS tblFields
ON tblFields.ID IN (subQ.lastFieldXId, subQ.lastFieldYId [, ...])
There is probably also a way using session variables, but I don't have the energy...
答案 1 :(得分:0)
select * from(
select p1.id,p1.id_person,p1.first_name,p1.last_name,
ifnull(p1.phone,p2ph.phone) phone ,ifnull(p1.email,p3em.email) email
from person p1
left join person p2ph on(p1.id_person=p2ph.id_person and p2ph.phone is not null)
left join person p3em on(p1.id_person=p3em.id_person and p3em.email is not null)
order by id_person,p1.id desc,p2ph.id desc,p3em.id desc
)t group by id_person;
verify at http://sqlfiddle.com/#!9/d2f44/6