我需要你的帮助。试图在php + jquery
中构建表单,并在某些功能方面遇到问题
例如,我有这段代码:
<form action="" method="post" id="multiform">
<!-- Product selector -->
<table class="multi" id="MultiRow">
<tr><td>
<select name="store[product][]" required>
<option value="" selected="selected">-Product-</option>
<option value="430">OCTA</option>
<option value="440">KASKO</option>
<option value="19041">TRAVEL</option>
<option value="19063">HOUSEHOLD</option>
</select>
</td>
<!-- /Product selector -->
</table>
<input type="submit" value="ok">
我该怎么办?如果选择的值是430或440,那么在右侧插入 s
<td><input type="text" id="motor[]" name="multiarray[vehicle_type][]"></td>
<td><input type="text" id="deadline[]" name="multiarray[end_date][]"></td>
<td><a class="del" href="#">DELETE BUTTON</a></td>
如果选择的值为19041或19063,则插入
<td><input type="text" id="location[]" name="multiarray[travel_location][]"></td>
<td><a class="del" href="#">DELETE BUTTON</a></td>
我需要在我写的地方添加button
和-delete button
:
<a class="del" href="#">DELETE BUTTON</a>
但是对于datepicker功能,我需要输入的id是唯一的,例如:id =“location1”,在下一个添加的行id =“location2”。
答案 0 :(得分:0)
$("#productselect").change(function(){
var select = document.getElementById("productselect");
var selecedproduct = select.options[select.selectedIndex].value;
$("tr[id^='forselect']").remove();
if(selecedproduct==430 || selecedproduct==440 )
{
var html ='<tr id="forselect"><td><input type="text" id="motor[]" name="multiarray[vehicle_type][]"></td>';
html +='<td><input type="text" id="deadline[]" name="multiarray[end_date][]"></td>';
html +='<td><a class="del" OnClick="removetags();return false;" href="#">DELETE BUTTON</a></td></tr>';
html +='<tr id="forselect"><td><a href="#" OnClick="adddatepicker();return false;">add datepicker </a> </td></tr>';
$("#MultiRow").append(html);
}
else if(selecedproduct==19041 || selecedproduct==19063 )
{
var html ='<tr id="forselect"><td><input type="text" id="location[]" name="multiarray[travel_location][]"></td>';
html +=' <td><a class="del" OnClick="removetags();return false;" href="#">DELETE BUTTON</a></td></tr>';
html +='<tr id="forselect"><td><a href="#" OnClick="adddatepicker();return false;">add datepicker </a> </td></tr>';
$("#MultiRow").append(html);
}
});
deldatepicker = function deldatepicker(id)
{
$("#remove"+id).remove();
}
adddatepicker = function adddatepicker()
{
var N = $("input[id^='location']").length;N++;
var html ='<tr id="remove'+N+'"><td><input type="text"id="location'+N+'" placeholder="date"></td><td><button OnClick="deldatepicker('+N+')">delete datepicker </button> </td></tr>';
$("#MultiRow").append(html);
$("#location"+N).datepicker();
}
removetags = function removetags()
{
$("tr[id^='forselect']").remove();
}
它可以帮助你工作。
答案 1 :(得分:0)
在这里。 由于你需要id是唯一的,我使用了Date.now()然后是object.now.getUTCMilliseconds()。这将确保当您删除并重新插入具有相同rowIndex的另一行时该事件不会崩溃。其余的都是微不足道的!
jQuery(document).ready(function(){
jQuery('select').on('change', function(e){
var tr = jQuery(this).closest('tr').get(0);
var cell = tr.insertCell(1);
var now = Date.now();
switch(jQuery('option:selected', this).val()){
case '430':
case '440':
cell.innerHTML = "<td><input type='text' id='motor[]' name='multiarray[vehicle_type][]'></td><td><input type='text' id='deadline[]' name='multiarray[end_date][]'></td><td><a class='del' href='#'>DELETE BUTTON</a></td><td><a class='del' href='#'>DELETE BUTTON</a></td>";
break;
cell.innerHTMl = "<td><input type='text' id='location"+now.getUTCMilliseconds()+"[]' name='multiarray[travel_location][]'></td><td><a class='del' href='#'>DELETE BUTTON</a></td><td><a class='del' href='#'>DELETE BUTTON</a></td>";
case '19041':
case '19063':
break;
}
})
});
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.0/jquery.min.js"></script>
<form action="" method="post" id="multiform">
<!-- Product selector -->
<table class="multi" id="MultiRow">
<tr><td>
<select name="store[product][]" required>
<option value="" selected="selected">-Product-</option>
<option value="430">OCTA</option>
<option value="440">KASKO</option>
<option value="19041">TRAVEL</option>
<option value="19063">HOUSEHOLD</option>
</select>
</td>
<!-- /Product selector -->
</table>
<input type="submit" value="ok">
&#13;