我是JavaScript的新手,所以请帮我解决这个问题: 我有数组,我想获得相同值的数量。我的阵列是:
var arr = ["red", "blue", "green", "red", "red", "gray"];
我想输出3,因为我有3个元素为红色。
这是我到目前为止所做的:
var numberOfSameElements = 0;
var arr = ["red", "blue", "green", "red", "red", "gray"];
for(var i = 1 ; i <arr.length;i++){
if(arr[i] === arr[i-1]){
numberOfSameElements++;
}
}
console.log(numberOfSameElements);
我一直得到1.请告诉我我做错了什么。非常感谢你!
答案 0 :(得分:3)
您可以将数组缩减为哈希映射,以确定每个单词的数量:
var words = ["red", "blue", "green", "red", "red", "gray"];
var wordCounts = words.reduce(function(counts, word) {
counts[word] = (counts[word] || 0)++;
}, { });
console.log(wordCounts);
// >> {
// red: 3,
// blue: 1,
// green: 1,
// gray: 1
// }
如果您想要复制的任何单词的名称,可以向下过滤原始数组:
var repeatedWords = words.filter(function(word) {
return wordCounts[word] > 1;
});
console.log(repeatedWords);
// >> ['red']
答案 1 :(得分:2)
在这里,您使用了一个循环并使用之前的值检查了当前值。但实际上你需要两个循环。
首先选择一个值。第二个将匹配所选择的值与所有其他值。我使用了found
标志来检查是否已找到重复值。试试这种方式,
var numberOfSameElements = 0;
var found = false;
var arr = ["red", "blue", "green", "red", "red", "gray"];
for(var i = 0 ; i <arr.length;i++){
for(var j = 0; j < arr.length; j++){
if(arr[i] === arr[j] && i != j){
if(!found){
numberOfSameElements++;
found = true;
}
}
}
found = false;
}
console.log(numberOfSameElements);
答案 2 :(得分:2)
如果要在阵列中找到重复的最大数量,首先必须统计它们。然后找到最大重复次数(fiddle):
function getLargestNumberOfSame(arr) {
var counterMap = arr.reduce(function (sameMap, item) { // create a map of same values
if (!sameMap[item]) {
sameMap[item] = 1;
} else {
sameMap[item]++;
}
return sameMap;
}, {});
var maxValues = Object.keys(counterMap).map(function(key) { // turn the map into array of max values
return counterMap[key];
});
return Math.max.apply(window, maxValues); // return the maximum value
}
答案 3 :(得分:1)
var numberOfSameElements = 1;
var arr = ["red", "blue", "green", "red", "red", "gray"];
arr = arr.sort();
var last;
for(var i = 0 ; i <arr.length -1 ;i++) {
//console.log(arr[i],arr[i+1]);
if(arr[i] == arr[i+1]){
numberOfSameElements++;
last = arr[i];
} else {
console.log(arr[i],"repert",numberOfSameElements,"times");
numberOfSameElements=1;
}
}
console.log(last,"repert",numberOfSameElements,"times");