Question

我在VS c ++ / cli中有一个String数组，并希望将其转换为float。你能帮帮我怎么办？

我尝试使用循环来完成它，但我想知道最简单的方法和有效的方法。

array<String^>^ Nettemprature = getDataString("Temp.csv", 11);
float Nettemp[50];
int n=0;
ifstream myfile ("Temp.csv");
if (myfile.is_open())
{
  while ( myfile.good() )
  {
    x=x+1;
    getline(myfile,Nettemprature[n]);
    Nettemp[n] = (float)(Convert::ToDouble(Nettemprature[n]));
    ...
  }
  ...
}

Answer 1

如果我试图在C ++ / CLI中将.csv文件（所有浮点数）读入数组，我会这样做：

#include "stdafx.h"

using namespace System;
using namespace System::Collections::Generic;
using namespace System::Diagnostics;
using namespace System::IO;
using namespace System::Linq;

float StringToFloat(String^ str)
{
    return float::Parse(str);
}

int main(array<System::String ^> ^args)
{
    Func<String^, float>^ stringToFloat = gcnew Func<String^, float>(StringToFloat);

    array<wchar_t,1>^ arr_chrSeps = { '\t', ',', '\n', '\r', ' ' };

    array<float, 1>^ arr_fltData =
        Enumerable::ToArray(
        Enumerable::Select<String^, float>(
        File::ReadAllText("c:/science/managed/ReadCsvToFloatArray/Floats.csv")
        ->Split(arr_chrSeps, StringSplitOptions::RemoveEmptyEntries), stringToFloat));

    Debug::WriteLine("There are {0} total floats in the list.",
        Enumerable::Count<float>(arr_fltData));

    Debug::WriteLine("There are {0} distinct floats in the list.",
        Enumerable::Count<float>(
        Enumerable::Distinct<float>(arr_fltData)));

   return 0;
}

如何在c ++ cli中将字符串数组转换为float数组？

1 个答案: