如何使用Maven程序集插件为特定文件设置文件权限?
以下工作正常,但它只包含已组装的存档中的 specificShFile.sh :
<assembly>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${project.build.outputDirectory}</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>specificShFile.sh</include>
</includes>
<fileMode>0755</fileMode>
</fileSet>
...
</fileSets>
...
</assembly>
我想要的是所有文件都包含在zip中,但只允许设置为该特定文件。
答案 0 :(得分:0)
您可以使用
<fileSets>
<fileSet>
<useDefaultExcludes/>
<outputDirectory/>
<includes/>
<excludes/>
<fileMode/>
<directoryMode/>
<directory/>
<lineEnding/>
<filtered/>
</fileSet>
</fileSets>
更具体这样
<fileSets>
<fileSet>
<directory>src/main/java</directory>
<outputDirectory>src/main/java</outputDirectory>
<includes>
<include>**</include>
</includes>
<useDefaultExcludes>true</useDefaultExcludes>
<fileMode>0644</fileMode>
<directoryMode>0755</directoryMode>
</fileSet>
</fileSets>
答案 1 :(得分:0)
非常感谢@SubOptimal的提示,这是对我有用的解决方案:
<assembly>
<formats>
<format>zip</format>
</formats>
<fileSets>
<fileSet>
<directory>${project.build.outputDirectory}</directory>
<outputDirectory>/</outputDirectory>
<excludes>
<exclude>specificShFile.sh</exclude>
</excludes>
</fileSet>
<fileSet>
<directory>${project.build.outputDirectory}</directory>
<outputDirectory>/</outputDirectory>
<includes>
<include>specificShFile.sh</include>
</includes>
<fileMode>0755</fileMode>
</fileSet>
...
</fileSets>
...
</assembly>