Question

此代码正常工作，直到我尝试添加＆＃34;响应＆＃34;用户必须输入＃＆＃34; p＆＃34;生成一个随机数6次。我无法识别#variable＆＃34;响应＆＃34;和＆＃34; yournum＆＃34;从第一个if语句开始。

就像我说它只适用于＆＃34; yournum＆＃34;变量 - 我只想要

用户点击＆＃34; P＆＃34;所以它一次生成一行。

import random
count = 0
response = 0
yournum = 0
print("Hello! Welcome to the Lottery Picker \n ")
print("Hit the letter P to pick each line or any other letter to quit ")
response = input()
while count < 6:
#response = 0
     if  yournum == 0 and response == "P":
         number = random.randint(1, 49)
         print("Your first number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1      
     elif yournum == 1 and response == "p":
         number = random.randint(1, 49)
         print("Your second number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1 
         print("Hit the letter P to another number ")
     #response = 0  
         response = input()        
     elif yournum == 2 and response == "p":
         number = random.randint(1, 49)
         print("Your third number is: " + str(number))         
         count = count + 1   
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 3 and response == "p":
         number = random.randint(1, 49)
         print("Your fourth number is: " + str(number))         
         count = count + 1  
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 4 and response == "p":
         number = random.randint(1, 49)
         print("Your fifth number is: " + str(number))         
         count = count + 1
         yournum = yournum + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input() 
     elif yournum == 5 and response == "p":
         number = random.randint(1, 49)
         print("And your powerball number is: " + str(number))      
         count = count + 1
         print("Hit the letter P to another number ")
     #response = 0  
         response = input()          
     else:
         count = count + 1
         print("Something is wrong with the lottery picker - goodbye ")

Answer 1

您错过了用户输入“P”的请求以及第一个if行中的latin1行。此外，您的后续if语句检查针对小写“p”的响应，而不是像第一个那样检查大写“P”。假设大写“P”是正确的，您更新的代码是：

response = input()

Python 3.4彩票选择器直接吹过我的if语句到其他地方

1 个答案: