如何使用带转义字符的变量进行sed？
这是我的档案：
$ cat file1.txt
abcdefg
<p class="text-muted">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2014. Core Team</p>
some more text
</head>
我试图使用以下命令（whcih在命令行中使用转义字符工作）
$ sed 's/<p class="text-muted">© 2014. Core Team<\/p>/99999/g' file1.txt
abcdefg
99999
some more text
99999
some more text
</head>
在使用变量的脚本中，但转义字符或其他字符对我来说越来越好：
这是我在我的脚本中的尝试，我可以grep使用变量工作，但我无法使sed工作。谁能帮我？
#!/bin/bash
###
# this is the text i want to find
# <p class="text-muted">© 2014. Core Team</p>
# and this is the text I want to replace depending on the year
# <p class="text-muted">© 2015. Core Team</p>
echo "hello this is a script to find a string and replace it with a string"
#s1='<p class="text-muted">© 2014. Core Team</p>' without escape characters
s1='<p class="text-muted">© 2014. Core Team</p>'
s2='<p class="text-muted">© 2015. Core Team</p>'
echo "s1="
echo "$s1"
echo "s2="
echo "$s2"
echo -e "\n\n\n\n\n\n\----------------\n\n\n\n\n\---------------"
grep "$s1" file1.txt #> file2.txt
sed 's/$s1/123/g' file1.txt #> file2.txt
#cat file2.txt
echo -e "\n\n\n\n\n\n\----------------\n\n\n\n\n\---------------"
-----------以下编辑1 - 进一步说明和/或供我参考----------------- < / p>
这是我要发布的文件：
$ cat file1.txt
abcdefg
123
<p class="text-muted">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2014. Core Team</p>
some more text
</head>
这是我的剧本
$ cat insertText2.sh
#!/bin/bash
###
# this is the text i want to find
# <p class="text-muted">© 2014. Core Team</p>
# and this is the text I want to replace depending on the year
# <p class="text-muted">© 2015. Core Team</p>
echo "hello this is a script to find a string and replace it with a string"
#s1='<p class="text-muted">© 2014. Core Team</p>' without escape characters
s1='<p class="text-muted">© 2014. Core Team</p>'
s2='<p class="text-muted">© 2015. Core Team</p>'
echo "s1="
echo "$s1"
echo "s2="
echo "$s2"
echo -e "\n\n-------grep on file1.txt--\n\n---------------"
grep "$s1" file1.txt #> file2.txt
echo -e "\n\n-------cat on file1.txt--\n\n---------------"
cat file1.txt
echo -e "\n\n-------sed on file1.txt--\n\n---------------"
#sed "s/$s1/123/g" file1.txt #> file2.txt
#sed "s|$s1|123|g" file1.txt #> file2.txt
sed "s|$s1|$s2|g" file1.txt #> file2.txt
#sed 's/123/ABC/g' file1.txt #> file2.txt
#cat file2.txt
这是我的脚本的输出
$ ./insertText2.sh file1.txt
hello this is a script to find a string and replace it with a string
s1=
<p class="text-muted">© 2014. Core Team</p>
s2=
<p class="text-muted">© 2015. Core Team</p>
-------grep on file1.txt--
---------------
<p class="text-muted">© 2014. Core Team</p>
<p class="text-muted">© 2014. Core Team</p>
-------cat on file1.txt--
---------------
abcdefg
123
<p class="text-muted">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2014. Core Team</p>
some more text
</head>
-------sed on file1.txt--
---------------
abcdefg
123
<p class="text-muted"><p class="text-muted">© 2014. Core Team</p>copy; 2015. Core Team</p>
some more text
<p class="text-muted"><p class="text-muted">© 2014. Core Team</p>copy; 2015. Core Team</p>
some more text
</head>
但这不是我想做的，而是取代了
<p class="text-muted">© 2014. Core Team</p>
与
<p class="text-muted"><p class="text-muted">© 2014. Core Team</p>copy; 2015. Core Team</p>
所以也许这与我的逃脱角色有关？
答案 0 :(得分：0)
sed "s|$s1|$s2|g" file1.txt我必须在变量中的＆符\上使用转义字符&。
这是我正在搜索的文件：
$ cat file1.txt
abcdefg
123
<p class="text-muted">© 2014. Core Team</p>
<p basic2014="test">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2014. Core Team</p>
<p basic2014="test">© 2014. Core Team</p>
some more text
</head>
这是我正在运行的脚本：
$ cat insertText3.sh
#!/bin/bash
###
# this is the text i want to find
# <p class="text-muted">© 2014. Core Team</p>
# and this is the text I want to replace depending on the year
# <p class="text-muted">© 2015. Core Team</p>
echo -e "hello this is a script to find a string and replace it with a string:\n"
#s1='<p class="text-muted">© 2014. Core Team</p>' without escape characters ## what I want to find and replace
s1='<p class="text-muted">\© 2014. Core Team</p>' ## need the single quotes here
s2='<p class="text-muted">\© 2015. Core Team</p>'
echo "this is what I want to find (note the escape character(\) in the variable to escape the ampersand(&) )(s1)="
echo "$s1"
echo -e "\n"
echo "this is what I want it to be replaced with (s2)="
echo "$s2"
echo -e "\n\n-------grep on file1.txt--\n\n---------------"
grep "$s1" file1.txt #> file2.txt
echo -e "\n\n-------cat on file1.txt--\n\n---------------"
cat file1.txt
echo -e "\n\n-------sed on file1.txt--\n\n---------------"
sed "s|$s1|$s2|g" file1.txt #> file2.txt works ## double quotes gives an error, single quotes runs with no errrors but does not alter the text
## because I have forward/backslash in the variable i use |
# #sed -i.bak2 "$c2" *.html
这是脚本运行的输出：
$ ./insertText3.sh
hello this is a script to find a string and replace it with a string:
this is what I want to find (note the escape character(\) in the variable to escape the ampersand(&) )(s1)=
<p class="text-muted">\© 2014. Core Team</p>
this is what I want it to be replaced with (s2)=
<p class="text-muted">\© 2015. Core Team</p>
-------grep on file1.txt--
---------------
<p class="text-muted">© 2014. Core Team</p>
<p class="text-muted">© 2014. Core Team</p>
-------cat on file1.txt--
---------------
abcdefg
123
<p class="text-muted">© 2014. Core Team</p>
<p basic2014="test">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2014. Core Team</p>
<p basic2014="test">© 2014. Core Team</p>
some more text
</head>
-------sed on file1.txt--
---------------
abcdefg
123
<p class="text-muted">© 2015. Core Team</p> ##<< 2014 has changed to 2015
<p basic2014="test">© 2014. Core Team</p>
some more text
<p class="text-muted">© 2015. Core Team</p> ##<< 2014 has changed to 2015
<p basic2014="test">© 2014. Core Team</p>
some more text
</head>