Question

我正在尝试为7天工作周期间的员工添加总工作时间，因为代码对我不起作用，不确定我做错了什么因为我不是PHP专家，想法好吗？

<?php 
            $time1 = $row_Roster['sunday_start'];
            $time2 = $row_Roster['sunday_end'];
            list($hours, $minutes, $seconds) = explode(':', $time1);
            $startTimestamp = mktime($hours, $minutes, $seconds);

            list($hours, $minutes, $seconds) = explode(':', $time2);
            $endTimestamp = mktime($hours, $minutes, $seconds);

            $add = $endTimestamp - $startTimestamp;
            if($seconds < 0) {
            $seconds+=60*60*24; 
            }
            $seconds = $add % 60;
            $minutes = ($add / 60) % 60;
            $hours = floor($add / (60 * 60));



            $sunday = sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);

            echo $sunday;
            if ($sunday >8)
            echo ('</br><span class="smallred">Long Shift</span>');
?>

有意义吗？

    list($hours, $minutes, $seconds) = explode(':', $time1);
    $Timestamp1 = mktime($hours, $minutes, $seconds);
    list($hours, $minutes, $seconds) = explode(':', $time2);
    $Timestamp2 = mktime($hours, $minutes, $seconds);
    list($hours, $minutes, $seconds) = explode(':', $time3);
    $Timestamp3 = mktime($hours, $minutes, $seconds);
    list($hours, $minutes, $seconds) = explode(':', $time4);
    $Timestamp4 = mktime($hours, $minutes, $seconds);

    $add = $Timestamp1 + $Timestamp2 + $Timestamp3 + $Timestamp4;
    if($seconds < 0) {
        $seconds+=60*60*24; 
    }
    $seconds = $add % 60;
    $minutes = ($add / 60) % 60;
    $hours = floor($add / (60 * 60));
    $total = sprintf('%02d:%02d:%02d', $hours, $minutes, $seconds);             
    echo $total;
?>

Answer 1

你这样做会变得复杂。

首先将所有格式化的日期放入数组（$formattedWorkTimeWeekdays）。

然后使用array_map()查看每一天并计算每天的总秒数并将其保存在$secondsWorkTimeWeekdays。

在此之后，您可以将所有秒数与array_sum()相加，并在变量$totalSecondsWorkTimeWeek中获得本周的总工作量（以秒为单位）。

最后只需计算出小时，分钟和秒数。

<?php

    $formattedWorkTimeWeekdays = [
            $monday,
            $tuesday,
            $wednesday,
            $thursday,
            $friday,
            $saturday,
            $sunday,
        ];

    $secondsWorkTimeWeekdays = array_map(function($formattedWorkTimeDay){
        list($hours, $minutes, $seconds) = explode(":", $formattedWorkTimeDay);
        return ($hours * 3600) + ($minutes * 60) + $seconds;
    }, $formattedWorkTimeWeekdays);

    $totalSecondsWorkTimeWeek = array_sum($secondsWorkTimeWeekdays);

    $hoursWorkTimeWeek = $totalSecondsWorkTimeWeek / 3600;
    $minutesWorkTimeWeek = ($totalSecondsWorkTimeWeek % 3600) / 60;
    $secondsWorkTimeWeek = ($totalSecondsWorkTimeWeek % 3600 % 60);

    echo $total = sprintf('%02d:%02d:%02d', $hoursWorkTimeWeek, $minutesWorkTimeWeek, $secondsWorkTimeWeek);

?>

修改

在您编辑后，您有两个完全不同的代码，这些代码根本不相关。对于您的第一次修订，我给出了上面的答案。

现在，在您编辑的代码中，您似乎只有2个日期。您可以创建两个DateTime对象并从中获取差异，例如

$workTimeStart = new DateTime($row_Roster['sunday_start']); $workTimeEnd = new DateTime($row_Roster['sunday_end']); $workTimeDifference = $workTimeStart->diff($workTimeEnd); echo $workTimeDifference->format("%h hours %i minutes %s seconds");

Answer 2

您可以使用gmdate function：

，而不是计算和调用sprintf

//the same code summing the weekdays seconds
$add = $Timestamp1 + $Timestamp2 + $Timestamp3 + $Timestamp4;
print gmdate("H:i:s", $add);

PHP时间加HH：MM：SS

2 个答案: