Question

作为一名温和的中级网络开发人员，我从未实际实施过联系表单。问题是我无法收到电子邮件。

HTML：

<form action="php/handleFormSubmit.php" id="contact-form" role="form" method="POST">
    <div class="ajax-hidden">
        <div class="form-group wow fadeInUp">
            <label class="sr-only" for="c_name">Name</label>
            <input type="text" id="c_name" class="form-control" name="c_name" placeholder="Name">
        </div>
        <div class="form-group wow fadeInUp" data-wow-delay=".1s">
            <label class="sr-only" for="c_email">Email</label>
            <input type="email" id="c_email" class="form-control" name="c_email" placeholder="E-mail">
        </div>
        <div class="form-group wow fadeInUp" data-wow-delay=".2s">
            <textarea class="form-control" id="c_message" name="c_message" rows="7" placeholder="Message"></textarea>
        </div>
        <button type="submit" class="btn btn-lg btn-block wow fadeInUp" data-wow-delay=".3s">Send Message</button>
    </div>
    <div class="ajax-response"></div>
</form>

PHP：

<?php

if(isset($_POST['submit']))
{

  $name = $_POST['c_name'];
  $visitor_email = $_POST['c_email'];
  $message = $_POST['c_message'];

  $email_from = "email@email.com";

  $email_subject = "New Form submission";

  $email_body = "You have received a new message from the user $name.\n".
                            "Here is the message:\n $message".

  $to = "email@email.com";

  $headers = "From: $email_from \r\n";

  $headers .= "Reply-To: $visitor_email \r\n";

  mail($to,$email_subject,$email_body,$headers);

}

if(isset($_POST['c_name'])){

    $res['sendstatus'] = 1;
    $res['message'] = 'Form Submission Successful';
    echo json_encode($res);
}

?>

我知道if(isset($_POST['submit']))在刷新/登陆时摆脱了烦人的电子邮件，但我的提交没有转到我的电子邮箱。

帮助？我很感激。

Answer 1

检查第一行，它说如果设置了$_POST['submit']，那么执行此操作{}。但你的html表单没有那个字段。

在表单中添加此字段：

<input type="hidden" name="submit">

Answer 2

通过Ajax发送邮件的代码

<?php
    if($_POST)
    {
        $to_email       = "er.shakun90@gmail.com"; //Recipient email, Replace with own email here

        //check if its an ajax request, exit if not
             if(!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') {

            $output = json_encode(array( //create JSON data
                'type'=>'error', 
                'text' => 'Sorry Request must be Ajax POST'
            ));
            die($output); //exit script outputting json data
             } 

        //Sanitize input data using PHP filter_var().
        $user_name      = filter_var($_POST["user_name"], FILTER_SANITIZE_STRING);
        //$user_email       = filter_var($_POST["user_email"], FILTER_SANITIZE_EMAIL);
        //$country_code = filter_var($_POST["country_code"], FILTER_SANITIZE_NUMBER_INT);
        $phone_number   = filter_var($_POST["user_phone"], FILTER_SANITIZE_NUMBER_INT);
        //$subject      = filter_var($_POST["subject"], FILTER_SANITIZE_STRING);
        $message        = filter_var($_POST["msg"], FILTER_SANITIZE_STRING);

        //additional php validation
        if(strlen($user_name)<4){ // If length is less than 4 it will output JSON error.
            $output = json_encode(array('type'=>'error', 'text' => 'Name is too short or empty!'));
            die($output);
        }


        if(!filter_var($phone_number, FILTER_SANITIZE_NUMBER_FLOAT)){ //check for valid numbers in phone number field
            $output = json_encode(array('type'=>'error', 'text' => 'Enter only digits in phone number'));
            die($output);
        }


        if(strlen($message)<3){ //check emtpy message
            $output = json_encode(array('type'=>'error', 'text' => 'Too short message! Please enter something.'));
            die($output);
        }

              $user_email = 'contact@sanktik.net';

        //email body
        $message_body = $message."\r\n\r\n-".$user_name."\r\nPhone Number :". $phone_number ;

              $sunject = "New enquiry from wesbite";

        //proceed with PHP email.
        $headers = 'From: '.$user_name.'' . "\r\n" .
        'Reply-To: '.$user_email.'' . "\r\n" .
        'X-Mailer: PHP/' . phpversion();

        $send_mail = mail($to_email, $subject, $message_body);

        if(!$send_mail)
        {
            //If mail couldn't be sent output error. Check your PHP email configuration (if it ever happens)
            $output = json_encode(array('type'=>'error', 'text' => 'Could not send mail! Please check your PHP mail configuration.'));
            die($output);
        }else{
            $output = json_encode(array('type'=>'message', 'text' => 'Hi '.$user_name .' Thank you for your interest.Our Team Member will get in touch with you shortly'));
            die($output);
        }
    }
    ?>

Answer 3

将您的按钮代码更改为：

<button type="submit" name="Submit" class="btn btn-lg btn-block wow fadeInUp" data-wow-delay=".3s">Send Message</button>

和你的php文件第一行：

if(isset($_POST['Submit']))

Answer 4

不要检查POST数组中是否存在该按钮。如果您单击按钮或通过Enter press提交表单，这是有道理的！我认为通过按Enter提交，提交按钮不存在！

以下解决方案不敏感：

if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
    // sent

重要的事情：

检查表单是否真实发布（见上文）
验证您的输入
Sanatize您的输入

之后，您可以执行自己的操作，例如：邮寄或保存到数据库。

HTML PHP表单不会将数据发送到电子邮件

4 个答案: