Question

我有一个从AJAX函数返回的JSON数组。该数组如下所示：

 {
    "date":[
        [
            "2015-05-29",
            "2015-05-12",
            "2015-04-30",
            "2015-03-30",
            "2015-02-27",
            "2015-02-26"
        ]
    ],
    "close":[
        [0,3,1,1,0,0]
    ],
    "high":[
        [1,3,2,1,0,1]
    ],
    "low":[
        [0,-1,0,-1,-1,-1]
    ]
}

我需要把'date'和'close'项目混合成一个看起来像这样的东西，对于JQPlot

var line1=[['2008-06-30 8:00AM',4], ['2008-7-30 8:00AM',6.5], ['2008-8-30 8:00AM',5.7], ['2008-9-30 8:00AM',9], ['2008-10-30 8:00AM',8.2]];

我想我需要循环这样的东西，但我不确定如何将值加入上面的新日期格式？

s3 = obj["close"][0];
dates = obj["date"][0];

 for( var i = 0; i < dates.length; i++ ){
  //not sure what to put here
}

Answer 1

// the data object you get back from your ajax
var data = {"date":[["2015-05-29","2015-05-12","2015-04-30","2015-03-30","2015-02-27","2015-02-26"]],"close":[[0,3,1,1,0,0]],"high":[[1,3,2,1,0,1]],"low":[[0,-1,0,-1,-1,-1]]}

var time = " 8:00AM"

var dates = data.date[0]
var s3 = data.close[0]

// make sure the data is valid 
// (`dates` and `s3` must have the same length in order to join them)
if (dates.length !== s3.length) {
    throw new Error('oh no! the data is invalid')
}

var line1 = []

for(var i = 0; i < dates.length; i++) {
    line1.push([dates[i] + time, s3[i]])
}

Answer 2

你快到了。在循环之前创建一个新数组。

var result = new Array;

然后在循环内部，您将在每次迭代时向该数组添加一个新项目。

result.push([dates[i], s3[i]]);

现在你的结果变量应该保存你想要的数组。

如何分离和合并JSON数组元素（用于JQPlot）

2 个答案: