仅在JSON中显示链接

Question

我有以下JSON字符串 -

{  
   "fruits":[  
      {  
         "name":"apples",
         "id":"1"
      },
      {  
         "name":"bananas",
         "id":"2"
      },
      {  
         "name":"oranges",
         "id":"3"
      },
      {  
         "name":"pears",
         "id":"4"
      },
      {  
         "name":"grapes",
         "id":"5"
      },
      {  
         "name":"strawberries",
         "id":"6"
      }
   ],
   "links":[  
      {  
         "source":"1",
         "target":"2"
      },
      {  
         "source":"1",
         "target":"3"
      },
      {  
         "source":"1",
         "target":"5"
      },
      {  
         "source":"4",
         "target":"5"
      },
      {  
         "source":"4",
         "target":"6"
      }
   ]
}

我的问题是有没有办法通过算法运行字符串，该算法只显示节点和连接的链接。因此，在示例中，JSON应该是（在删除冗余数据之后） -

{  
   "fruits":[  
      {  
         "name":"apples",
         "id":"1"
      },
      {  
         "name":"pears",
         "id":"4"
      },
      {  
         "name":"grapes",
         "id":"5"
      }
   ],
   "links":[  
      {  
         "source":"1",
         "target":"5"
      },
      {  
         "source":"4",
         "target":"5"
      }
   ]
} 

葡萄与苹果和梨都有关系。我已经创建了一个算法来删除任何有效的重复项，但是不能破解它以显示链接条目。

我已遍历所有目标值

var lookup = {};
                var result = [];
                var links = jsonString['links'];
                for (var item, i = 0; item = links[i++];) {
                    var name = item.target;

                    if (!(name in lookup)) {
                        lookup[name] = 1;

                        // remove unique values to leave only multiple occurances 
                        // then based on the source and target values removes none related from fruits and rebuild JSON

                    }
                }