Question

我需要进行查询并获取某种数据。我有2个表，用户和连接，我需要获得每个用户每月和每年连接的次数。

users             connections
...........    ................
john              10/02/2014
john              15/02/2014
john              03/01/2015
john              06/02/2015

是否有机会以这种格式获取此信息：

 john=>
   [0]=>2014
     [0]=>02
       'total' =>2
   [1]=>2015
     [0]=>01
       'total' => 1
     [1]=>02
       'total' => 2
     [2]=>03
       'total'=> 1

我正在使用Codeigniter和PHP。

回答@CodeGodie到目前为止我所做的是：

public function getPeriodicity(){
    $this->db->select('u.vusr_user, extract (MONTH from (to_timestamp(c.vuc_log_in))) as month, extract (YEAR from (to_timestamp(c.vuc_log_in))) as yearly, COUNT(c.vuc_log_in)');
    $this->db->from('vts_users_conn c');
    $this->db->join('vts_users u', 'c.vuc_vusr_id = u.vusr_id');
    $this->db->group_by('u.vusr_user, month, yearly','asc');
    $query = $this->db->get();
    return $query->result_array();
  }

Answer 1

As a general rule, if you can access the data and see in your mind how you want that data to look, then it's pretty much possible to get it to do that. It's just a matter of working out the process.

In your case, I would do the following steps:

Order the data by users, then by date so everything is nicely together
Loop through the data and each time, check that the current user is the same as the last one. if it's not, create a new array key
split the date into the parts you want
check the user array for the key relating to year for that user. If the year exists, search for the month. If the month exists, add 1 to the total for that month. If the year and/or month don't exist, create the keys and set the total to be 1 for that month

Once the records have been processed, you should have the data in the format you need.

Answer 2

假设您使用Codeigniter的$this->db->result_array()获取数据库结果，您的初始数组将如下所示：

$res = array(
    array(
        "name" => "john",
        "date" => "10/02/2014"
    ),
    array(
        "name" => "john",
        "date" => "15/02/2014"
    ),
    array(
        "name" => "john",
        "date" => "03/01/2015"
    ),
    array(
        "name" => "john",
        "date" => "06/02/2015"
    ),
    array(
        "name" => "john",
        "date" => "06/03/2015"
    )
);

为了将此数组更改为您想要的输出，我将执行以下操作：

foreach ($res as $row) {
    $date_arr = explode("/", $row['date']);
    $n = $row['name'];
    $y = $date_arr[2];
    $m = $date_arr[1];

    if (!isset($final[$n]))
        $final[$n] = array();

    if (!isset($final[$n][$y]))
        $final[$n][$y] = array();

    if (!isset($final[$n][$y][$m])) {
        $final[$n][$y][$m] = array("total" => 1);
    } else {
        $final[$n][$y][$m]["total"] = $final[$n][$y][$m]["total"] + 1;
    }
}

如果您var_dump得出最终结果（var_dump($final)），您将获得以下结果：

array (size=1)
  'john' => 
    array (size=2)
      2014 => 
        array (size=1)
          '02' => 
            array (size=1)
              'total' => int 2
      2015 => 
        array (size=3)
          '01' => 
            array (size=1)
              'total' => int 1
          '02' => 
            array (size=1)
              'total' => int 1
          '03' => 
            array (size=1)
              'total' => int 1

希望这有帮助。

使用SQL和Codeigniter返回一个4维数组

2 个答案: