Question

我的申请给了我一个字符串，如1天15分钟或15小时10分钟等。我想将此字符串转换为Date对象。我正在尝试这样的事情

Date afterAddingTenMins = new Date(t + (Integer.valueOf(duration) * ONE_MINUTE_IN_MILLIS));

但是这给了我无效的整数异常，因为字符串包含像小时和分钟这样的单词什么是最好的方法。

谢谢。

Answer 1

这是一个scala版本：

object PrettyTimeParser {
  private val YEAR_REGEX = """(?<YEAR>\d+)\s*years?""".r
  private val MONTH_REGEX = """(?<MONTH>\d+)\s*months?""".r
  private val WEEK_REGEX = """(?<WEEK>\d+)\s*weeks?""".r
  private val DAY_REGEX = """(?<DAY>\d+)\s*days?""".r
  private val HOUR_REGEX = """(?<HOUR>\d+)\s*hours?""".r
  private val MINUTE_REGEX = """(?<MINUTE>\d+)\s*minutes?""".r

  private def lookup(regex: scala.util.matching.Regex, s: String): Int = {
    Try(regex.findAllIn(s).toList.headOption.map(_.split(" ")).map(_(0).toInt)).getOrElse(None).getOrElse(0)
  }

  def parse(str: String): Option[DateTime] = {
    val year = lookup(YEAR_REGEX, str)
    val month = lookup(MONTH_REGEX, str)
    val week = lookup(WEEK_REGEX, str)
    val day = lookup(DAY_REGEX, str)
    val hour = lookup(HOUR_REGEX, str)
    val minute = lookup(MINUTE_REGEX, str)

    val now = DateTime.now()

    val dt = DateTime.now().plusYears(year)
      .plusMonths(month)
      .plusWeeks(week)
      .plusDays(day)
      .plusHours(hour)
      .plusMinutes(minute)

    if (dt.isAfter(now.getMillis)) Option(dt) else None
  }

}

Answer 2

您可以通过正则表达式提取它们：

    String time = "1 day 15 min";
    Pattern pat = Pattern.compile("(?<DAY>\\d+)\\s*days?|(?<HOUR>\\d+)\\s*hours?|(?<MIN>\\d+)\\s*min");
    Matcher m = pat.matcher(time);
    int day = 0, hour = 0, min = 0;
    while (m.find()) {
        if (m.group("DAY") != null) day = Integer.parseInt(m.group("DAY"));
        if (m.group("HOUR") != null) hour = Integer.parseInt(m.group("HOUR"));
        if (m.group("MIN") != null) min = Integer.parseInt(m.group("MIN"));
    }
    System.out.printf("%d day %d hour %d min%n", day, hour, min);
    // -> 1 day 0 hour 15 min

Answer 3

理想的解决方案是更改数据源以提供JSON或其他可靠格式：

{
    days: 15,
    hours: 9,
    minutes: 30
}

然后您可以使用JSON库来解析数据。

但是如果你处理那个字符串，你可以像saka1029那样去正则路由，甚至更简单，只需手动解析字符串：

String test = "15 hour 10 min";
    String[] testArray = test.split(" ");
    long additionalDuration = 0;
    for(int i = 0; i < testArray.length; i+=2) {
        switch(testArray[i+1].toLowerCase()) {
            case "day":
            case "days":
                additionalDuration += Integer.parseInt(testArray[i]) * (1000 * 60 * 60 * 24);
                break;
            case "hour":
            case "hours":
                additionalDuration += Integer.parseInt(testArray[i]) * (1000 * 60 * 60);
                break;
            case "minute":
            case "minutes":
                additionalDuration += Integer.parseInt(testArray[i]) * (1000*60);
                break;
            default:
                System.out.println("Could not parse unit: \""+testArray[i+1]+"\"");
        }
    }
    Date futureDate = new Date(new Date().getTime() + additionalDuration);

Java：将包含天，小时，分钟的字符串转换为Date对象

3 个答案: