这是一个在控制台和绘图面板中创建游戏连接四的类,我在connectedFour
方法中遇到问题,它确定某人是否连续获得了4张光盘。问题是,我不知道如何设置我的for循环来检查连续四个光盘的阵列
这是我的代码:
import java.util.*;
import java.awt.*;
public class ConnectFour{
public static void main(String[] args){
//board
DrawingPanel panel = new DrawingPanel(550,550);
int rowAvailable;
Graphics g = panel.getGraphics();
g.drawLine(0,0,0,500);
g.drawLine(0,0,500,0);
g.drawLine(500,0,500,427);
g.drawLine(0,427,500,427);
for(int i = 0; i< 6; i++){
for(int j= 0; j<= 6; j++){
g.setColor(Color.YELLOW);
g.fillRect(j*71,i*71,71,71);
g.setColor(Color.WHITE);
g.fillOval(j*71,i*71,71,71);
}
}
//setBlankArray
Scanner console = new Scanner(System.in);
char[][] board = new char[6][7];
for(int j = 0;j <= 6; j++){
for(int i= 0; i < 6; i++){
board[i][j] = ' ';
}
}
boolean isBlack = true;
boolean isRed = false;
int column = 0;
boolean playersTurn = true;
boolean rightNum = false;
//oneTurn
while(getWinner(board, playersTurn)){
//while(playersTurn == true){
rightNum = false;
if(isBlack == true){
// displayCurrentPlayer
System.out.println("Black's Turn");
g.setColor(Color.WHITE);
g.drawString("Red Disc's Turn",200, 450);
g.setColor(Color.BLACK);
g.drawString("Black Disc's Turn",200, 450);
}
else{
// displayCurrentPlayer
System.out.println("Red's Turn");
g.setColor(Color.WHITE);
g.drawString("Black Disc's Turn",200, 450);
g.setColor(Color.RED);
g.drawString("Red Disc's Turn",200, 450);
}
System.out.print("Choose a column to place your disk (1-7): ");
while(rightNum == false){
column = (console.nextInt()) -1;
if(column >= 0 && column < 7 && board[0][column] == ' '){
rightNum = true;
}
else{
System.out.print("Try again: ");
}
}
drawBoard(column, board, isBlack, isRed, board, g);
isBlack = !isBlack;
}
if(isBlack == false){System.out.println("Congratulations Black Player");}
else{System.out.println("Congratulations Red Player");}
// use the while loop to say try again if the column is filled.
}
public static void drawBoard(int column, char[][] board, boolean isBlack, boolean isRed, char[][] availability,Graphics g){
char player = ' ';
if(isBlack == true){
g.setColor(Color.BLACK);
player = 'b';
}
else{
g.setColor(Color.RED);
player = 'r';
}
int x = 0;
int row = 5;
while(board[row-x][column] != ' '){
x++;
}
row = row-x;
g.fillOval((column * 71),(row * 71), 71,71);
board[row][column] = player;
}
public static boolean getWinner(char[][] board, boolean playersTurn){
int verticalCount = 0;
boolean isVertical = false;
for(int i = 6; i >= 0; i--){
verticalCount = 0;
for(int j = 5; j > 0; j--){
if(board[j][i] == board[j-1][i] && board[j][i] != ' '){
verticalCount++;
}
if(verticalCount == 4){
isVertical = true;
}
}
}
int horizontalCount = 0;
boolean isHorizontal = false;
for(int i =1; i <= 5; i++){
for(int j =1; j<6; j++){
if(board[j][i] == board[j][i+1] && board[j][i] != ' '){
horizontalCount++;
}
if(horizontalCount == 3){
isHorizontal = true;
}
}
}
int diagonalCount = 0;
boolean isDiagonal = false;
// for(int i = 0; i<=6; i++){
// for(int j =0; j<6; j++){
// if(board[i][j-1] == board[i][j]){
// diagonalCount++;
// }
// }
// }
if(isVertical || isHorizontal || isDiagonal){
playersTurn = false;
}
else{
playersTurn = true;}
return playersTurn;
}
}
答案 0 :(得分:0)
我会通过检查光盘放置后是否符合游戏获胜条件来实现此目的。这样,您不会在每次移动后迭代整个电路板。
无论如何,试试这个:
替换
while (gameWon == false ){
与
while (!connectedFour(board, playersTurn)) {
我认为这不会完全解决您的问题,因为您发布的代码看起来有一些其他问题。