Question

我正在尝试比较行级别的两个csv文件。如果匹配字符串，则打印正确的字符串。

import csv
file1 = open('/a1.csv','rb')
file2 = open('/test.csv','rb')
myfile = csv.reader(file1, delimiter=',')
myfile1 = csv.reader(file2, delimiter=',')
    for row in myfile:
        for row1 in myfile1:
            new=""
            if row1[0] == row:
                new = row[0]
            else:
                new = row1[0]
            print new

a1.csv包含样本输入：

A,a,a1,a2
B,b,b1,b5

test.csv包含样本输入：

a
a!

如果字符串匹配，例如“a”==“A，a，a1，a2”那么我想打印'A'并且如果没有匹配，例如“a！” ==“A，a，a1，a2”然后需要打印'a！'

我的代码是打印“a”和“a！”没有比较的输出。这是比较字符串的错误方法吗？

Answer 1

请尝试此操作（请注意in语句而不是＆＃39; ==＆＃39;）另请注意打印逻辑已更改：

import csv
file1 = open('/a1.csv','rb')
file2 = open('/test.csv','rb')
a1 = csv.reader(file1, delimiter=',')
test = csv.reader(file2, delimiter=',')


for row1 in test:
    new=""
    found = False
    for row in a1:
        if row1[0] in row:
            new = row[0]
            found = True
    if not found:
        new = row1[0]
    print new
    file1.seek(0)

Python中的行级字符串比较

1 个答案: