我有这个练习来解决:
使用_.each从1,1000(含)
创建数组
我真的不知道该怎么做,我认为这是不可能的......
你能帮助我吗?
答案 0 :(得分:3)
您可以通过将所需的数组长度传递给Array构造函数来创建一个包含1000个元素的空数组,然后使用_.each()
为数组中的每个索引赋值。
var array = _.each(new Array(1000), function(v, i, a) {
a[i] = i + 1;
});
console.log(array)

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答案 1 :(得分:1)
问题上的functional-programming
标记是线索。 :-)在函数式编程中,通常将循环写为递归。那么我们如何使用递归来使用_.each
来构建数组呢?通过回调调用它:
var array = _.each([1], function cb(e, i, a) {
if (a.length < 1000) {
a.push(a.length + 1);
_.each(a, cb);
}
});
snippet.log(array.length);
snippet.log(array.join(", "));
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或者真的顽皮,我们可以从一个1000个字符的字符串开始:
var oneThousand =
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789" +
"01234567890123456789012345678901234567890123456789";
var array = [];
_.each(oneThousand, function(e, i) {
array[i] = i + 1;
});
snippet.log(array.length);
snippet.log(array.join(", "));
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......但我确定这是在作弊。