Question

假设我使用循环生成变量列表或字典：

a = {}
b = []
k = 1
count = TaskBox.objects.all().count()
output = ""
while k <= count:
    ck = str(k)
    newline = output.join("box"+ck+" = InboxEntry.objects.filter(box="+ck+")")
    c.append(newline)
    b['box'+ck] = "InboxEntry.objects.filter(box="+ck+")"
    k += 1

产生：['box1 = InboxEntry.objects.filter（box = 1）'，'box2 = InboxEntry.objects.filter（box = 2）']

和 {'box2'：'InboxEntry.objects.filter（box = 2）'，'box1'：'InboxEntry.objects.filter（box = 1）'}

如何解压缩任何结构中的变量以便在views.py？

中使用

我最终会寻找类似的东西：

def display_prdInboxEntry(request, id):
    if request.method == 'POST':
        form = PrdInboxForm(request.POST)
        if form.is_valid():
            form.save()
            return HttpResponseRedirect('taskmanager/display/'+ id +'/')
        else:
            form = PrdInboxForm(request.POST)
            return HttpResponseRedirect('taskmanager/display/'+ id +'/')

    else:
        form = PrdInboxForm()
        user = request.user
        u = UserProfile.objects.get(pk=id)
        boxrecords = TaskBox.objects.all()
        assignedrecords = InboxEntry.objects.filter(assigned_by=u)

        '''loop code'''
        a = {}
        b = []
        k = 1
        count = TaskBox.objects.all().count()
        output = ""
        while k <= count:
            ck = str(k)
            newline = output.join("box"+ck+" =  InboxEntry.objects.filter(box="+ck+")")
            c.append(newline)
            b['box'+ck] = "InboxEntry.objects.filter(box="+ck+")"
            k += 1

        '''need to pull these values from the product of the loop'''
        box1 = InboxEntry.objects.filter(box=1)
        box2 = InboxEntry.objects.filter(box=2)

        records = InboxEntry.objects.filter(assigned_to=u).order_by('status')
        return render_to_response('taskmanager/taskmanager_view.html', {'form': form, 'assignedrecords': assignedrecords, 'records': records, 'boxrecords': boxrecords, 'box1' : box1, 'box2' : box2, 'user': user}, context_instance=RequestContext(request))

Answer 1

好的，所以我不需要提取＆＃34;字典中的变量以便使用它们。我只是在我的视图代码中放置一个循环来生成变量字典，然后用我的http响应字典连接该字典：

def display_prdInboxEntry(request, id):
    if request.method == 'POST':

    '''form code'''

    else:
        form = PrdInboxForm()
        user = request.user
        u = UserProfile.objects.get(pk=id)
        assignedrecords = InboxEntry.objects.filter(assigned_by=u)
        records = InboxEntry.objects.filter(assigned_to=u).order_by('status')
        boxrecords = TaskBox.objects.all()
        boxes = TaskBox.objects.all().count()

        ''' variable generator'''
        boxdict = {}
        for x in range(1, boxes + 1):
            boxdict['box{0}s'.format(x)] = InboxEntry.objects.filter(box='{0}'.format(x))


        returndict = {'form': form, 'assignedrecords': assignedrecords, 'records': records, 'boxrecords': boxrecords, 'user': user}

        ''' return dictionary concatenation'''
        z = returndict.copy()
        z.update(boxdict)
        return render_to_response('taskmanager/taskmanager_view.html', z, context_instance=RequestContext(request))

不知道它是多么传统，并且对模板进行有效编码将是一个挑战 - 但它有效，并且允许用户在管理中即时创建任务框，而无需适应视图代码 - 这就是我所追求的。

访问列表或字典值以在视图函数中使用

1 个答案: