我有一个数据库,其中包含州名,区,城市,区域大小等区域详细信息......
现在我想从州名中计算一个区域值,并将该值分配给某个变量以显示html页面。
Example: The tamil nadu state includes total of 30 districts.
查询状态列表,
$qry = "SELECT DISTINCT state_Name FROM area_info ORDER BY state_Name";
怎么做...有人请帮助我..
答案 0 :(得分:2)
尝试此查询:
SELECT count(district)
FROM area_info
GROUP BY state_Name
答案 1 :(得分:2)
试试这个
$qry = "SELECT DISTINCT state_Name, COUNT(*) AS district FROM area_info Group BY state_Name" ;
答案 2 :(得分:2)
要获取记录的计数,您可以使用以下查询
echo "The tamil nadu state includes total of $totaldist districts.";
然后分配这个变量你可以这样写:
{{1}}
答案 3 :(得分:2)
您应该尝试这一点,肯定会解决您的疑问。
$qry = "SELECT state_name, COUNT(district) As TotalData FROM area_info GROUP BY state_name";
答案 4 :(得分:1)
列出州名及其中的地区数量:
SELECT state_Name, COUNT(district)
FROM area_info
GROUP BY state_Name;