实施您的功能枚举

Question

我一直收到IllegalStateException：在maven上的web应用程序中安装togglz时找不到FeatureManager。我完全按照指示进行了操作。在我的maven应用程序中，我在pom.xml文件中有以下设置：

<dependency>
<groupId>org.togglz</groupId>
<artifactId>togglz-core</artifactId>
<version>2.1.0.Final</version>
</dependency>

<dependency>
<groupId>org.togglz</groupId>
<artifactId>togglz-console</artifactId>
<version>2.1.0.Final</version>
</dependency>

<dependency>
<groupId>org.togglz</groupId>
<artifactId>togglz-servlet</artifactId>
<version>2.1.0.Final</version>
</dependency>

<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>

以及web.xml文件中的以下内容：

<context-param>
<param-name>org.togglz.core.manager.TogglzConfig</param-name>
<param-value>com.test.test.ana.FeatureFlagConfiguration</param-value>
</context-param>

<servlet>
<servlet-name>TogglzConsoleServlet</servlet-name>
<servlet-class>org.togglz.console.TogglzConsoleServlet</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>TogglzConsoleServlet</servlet-name>
<url-pattern>/togglz/*</url-pattern>
</servlet-mapping>

这个示例maven app运行正常，但是当我尝试转到togglz虚拟目录时，它会抛出IllegalStateException：找不到FeatureManager错误，它没有提供更多细节。关于那个错误究竟意味着什么的任何建议？我只是想尝试一个使用togglz的示例项目。我不能使用spring或cdi，只能使用servlet。（是的，我配置了servlet 3.0）

提前致谢，

编辑：这是确切的堆栈跟踪：

    [ERROR   ] SRVE0777E: Exception thrown by application class 'org.togglz.core.context.FeatureContext.getFeatureManager:49'
java.lang.IllegalStateException: Could not find the FeatureManager. For web applications please verify that the TogglzFilter starts up correctly. In other deployment scenarios you will typically have to implement a FeatureManagerProvider as described in the 'Advanced Configuration' chapter of the documentation.
    at org.togglz.core.context.FeatureContext.getFeatureManager(FeatureContext.java:49)
    at org.togglz.core.manager.LazyResolvingFeatureManager.getDelegate(LazyResolvingFeatureManager.java:24)
    at org.togglz.core.manager.LazyResolvingFeatureManager.getCurrentFeatureUser(LazyResolvingFeatureManager.java:49)
    at org.togglz.console.TogglzConsoleServlet.isFeatureAdmin(TogglzConsoleServlet.java:68)
    at org.togglz.console.TogglzConsoleServlet.service(TogglzConsoleServlet.java:55)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:668)
    at com.ibm.ws.webcontainer.servlet.ServletWrapper.service(ServletWrapper.java:1285)
    at [internal classes]

Answer 1

如果您处于普通的Servlet环境中，则在添加Maven依赖项后必须执行以下操作：

实施您的功能枚举

这通常如下所示：

public enum MyFeatures implements Feature {

    @EnabledByDefault
    @Label("First Feature")
    FEATURE_ONE,

    @Label("Second Feature")
    FEATURE_TWO;

    public boolean isActive() {
        return FeatureContext.getFeatureManager().isActive(this);
    }

}

通过实现TogglzConfig

配置Togglz

一个典型的例子如下：

public class MyTogglzConfiguration implements TogglzConfig {

    public Class<? extends Feature> getFeatureClass() {
        return MyFeatures.class;
    }

    public StateRepository getStateRepository() {
        return new FileBasedStateRepository(new File("/tmp/features.properties"));
    }

    public UserProvider getUserProvider() {
        return new ServletUserProvider();
    }

}

在web.xml

中注册配置类

在普通的Servlet环境中，您现在必须通过向web.xml添加类似的内容来注册TogglzConfig实现：

<context-param>
  <param-name>org.togglz.core.manager.TogglzConfig</param-name>
  <param-value>com.example.myapp.MyTogglzConfiguration</param-value>
</context-param>

您还应明确告诉Togglz您不希望它从Spring或CDI查找FeatureManager，而是创建和管理实例本身：

<context-param>
  <param-name>org.togglz.FEATURE_MANAGER_PROVIDED</param-name>
  <param-value>true</param-value>
</context-param>

在Servlet 3.0环境中，通常会自动拾取TogglzFilter。但是，您也可以手动注册：

<filter>
  <filter-name>TogglzFilter</filter-name>
  <filter-class>org.togglz.servlet.TogglzFilter</filter-class>
</filter>
<filter-mapping>
  <filter-name>TogglzFilter</filter-name>
  <url-pattern>/*</url-pattern>
</filter-mapping>

我希望这有帮助。如果这仍然无效，请在您的问题中包含完整的堆栈跟踪。

Togglz抛出IllegalStateException错误

1 个答案:

实施您的功能枚举

通过实现TogglzConfig

在web.xml