Question

我在布局中为列表中的各个项目定义了一个imageview，并将它们设置为不可见。当我点击一个按钮时，它们将会显示，但我无法采取此行动。我想达到这个效果。这是我的代码：

//file:list_view_test.jade
Alloy    
    Window#win
        Button#btn(title = "Show" onClick = "show_the_image_view")

        ListView#list_view(defaultItemTemplate = "list_style")
            Templates
                ItemTemplate(name = "list_style")
                    View#item_view(bindId = "bind_item_view")
                        ImageView#image_view(bindId = "bind_image_view")

        ListSection
            ListItem(bind_item_view:backgroundImage = "/images/backgroundImage_1.png"
                     bind_image_view:image = "/images/unchecked_image.png")
            ListItem(bind_item_view:backgroundImage = "/images/backgroundImage_2.png"
                     bind_image_view:image = "/images/unchecked_image.png")

//file:list_view_test.stss
#item_view{
    width:100%;
    height:10% 
}

#image_view{
    top:0;
    left:0;
    width:20%;
    height:20%;

    visible:false
}

//file:list_view_test.coffee
show_the_image_view = ->
    if "Show" == $.btn.getTitle()
        $.btn.setTitle("Hide")
        //$.image_view.setVisible(true) (this code had been commented, cause it's wrong)
    else if "Hide" == $.btn.getTitle()
        $.btn.setTitle("Show")
        //$.image_view.setVisible(false) (this code had been commented, cause it's wrong)

$.list_view.addEventListener('itemclick', = (e) ->
    if e.itemIndex == 0
        //$.image_view.setImage('/images/checked_image.png') (this code had been commented, cause it's wrong)

    else if e.itemIndex == 1
        //$.image_view.setImage('/images/checked_image.png') (this code had been commented, cause it's wrong)

有没有人有一个很好的方法来解决这个问题？

如何获取listView（Titanium）的listItem中的children-item？

0 个答案: