我有一条最合适的线性线。我需要的数据点不会改变我的最佳匹配线

Question

我正在介绍如何拟合最合适的线条。我有一条简单的直线：y = 1x + 0。我正在尝试获得分散的数据点，我可以放在散点图中，这将使我的最佳拟合线保持相同的等式：y = 1x + b。

我很乐意在R或Excel中学习这种技术 - 无论哪种更容易。

谢谢！

Answer 1

First generate a set of points x and y that fit your equation exactly. Then, add an error vector to y that is orthogonal to x. To do this, generate a vector r, that is same length as y. Then compute the residuals from the least squares fit of r to x, e = r - rhat, where rhat = bhat + x*ahat. (bhat and ahat are the least squares fit to this r, not your original b). Add e to y.