Question

我需要在查询中放置一个where子句，但我没有达到正确的语法。

       /*
        * Support listing and POSTing back Origem entities (e.g. from inside an
        * HtmlSelectOneMenu)
        */

         public List<Origem> getAll()
   {

      CriteriaBuilder cb = this.entityManager.getCriteriaBuilder();
        CriteriaQuery<Origem> criteria = cb.createQuery(Origem.class);
        Root<Origem> root = criteria.from(Origem.class);
        return this.entityManager.createQuery(
                criteria.select(root).where())
                .getResultList();
   }

在我的where子句中想要带来所有＆＃34; origem＆＃34; id等于登录用户。像这样：

例如：select * from origin where origem.id = loginBean.origem.getId

Answer 1

只需将 criteria.add（Restrictions.eq（））用于您的条件，我认为如果ID是唯一的，您需要使用.uniqueResult()从您的条件中获取所需结果，你的代码应该是这样的：

CriteriaBuilder cb = this.entityManager.getCriteriaBuilder();
Criteria cr = cb.createCriteria(Origem.class);
// add the restriction here
cr.add(Restrictions.eq("id", loginBean.origem.getId));
Origem root = (Origem) cr.uniqueResult();

Answer 2

使用criteria.addRestrictions（Restrictions.eq（＆＃34; propertyName＆＃34;，＆＃34; propertyValue＆＃34;）;

public List getAll（ long idFromLoginBeanOrigin ） {

  CriteriaBuilder cb = this.entityManager.getCriteriaBuilder();
    CriteriaQuery<Origem> criteria = cb.createQuery(Origem.class);

criteria.add（Restrictions.eq（＆＃34; origem.id＆＃34;，idFromLoginBeanOrigin））;

    Root<Origem> root = criteria.from(Origem.class);
    return this.entityManager.createQuery(
            criteria.select(root).where())
            .getResultList();

}

我输入它现在可能有拼写错误，请检查！

语法where where子句与标准协商

2 个答案: