Question

我有两个viewcontrollers在swift中自定义'push'Segue。当我在tableview中选择一行时，它完美地显示了一个包含三个选项的警告框。我的问题是当我选择第一个选项（Ver Mapa）更改为anotherviewcontroller时，它不起作用。什么都不做。我该如何解决呢？

override func prepareForSegue(segue: (UIStoryboardSegue!), sender: AnyObject!) {


    var refreshAlert = UIAlertController(title: "Menu", message: "Seleccione una opcion", preferredStyle: UIAlertControllerStyle.Alert)

    refreshAlert.addAction(UIAlertAction(title: "Ver Mapa", style: .Default, handler: { (action: UIAlertAction!) in
        if (segue.identifier == "go_to_mapa") {
            var svc = segue!.destinationViewController as Mapa;
            self.performSegueWithIdentifier("go_to_mapa", sender: self)
            svc.cuenta = self.cuenta
            svc.user = self.user
            svc.password = self.password

            let indexPath = self.tableView.indexPathForSelectedRow();
            let currentCell = self.tableView.cellForRowAtIndexPath(indexPath!) as UITableViewCell!;

            svc.Device = currentCell.detailTextLabel!.text!
            svc.desc = currentCell.textLabel!.text!


        }



    }))
    refreshAlert.addAction(UIAlertAction(title: "Detalle Vehiculo", style: .Default, handler: { (action: UIAlertAction!) in
        println("Detalle Vehiculo")
    }))
    refreshAlert.addAction(UIAlertAction(title: "Ejecutar comandos", style: .Default, handler: { (action: UIAlertAction!) in
        println("Ejecutar comandos")
    }))

    refreshAlert.addAction(UIAlertAction(title: "Cancelar", style: .Default, handler: { (action: UIAlertAction!) in
        self.back()
    }))

    presentViewController(refreshAlert, animated: true, completion: nil)

}

Answer 1

你的代码搞砸了。

显示提醒的代码不属于prepareForSegue。您不应该在prepareForSegue中执行任何用户界面。您也不应该在performSegueWithIdentifier内拨打prepareForSegue。在您或用户触发segue之后，系统会在显示新视图控制器之前调用prepareForSegue方法。它让你有机会进行设置。

您发布的代码不太可能显示警告。

这是你想做的事情：

如果要在用户选择表视图中的单元格时触发警报，请实施表格视图委托方法didSelectRowAtIndexPath:。在该方法中，创建并显示警报控制器。当用户选择一个选项时，如果你想触发一个segue，你应该调用performSegueWithIdentifier。

一旦您触发了segue，系统就会调用您的prepareForSegue方法

Answer 2

在动作处理程序中，你必须调用 segue，而不是检查它。您在prepareForSegue ...

中查看了segue

// calling the segue
self.performSegueWithIdentifier("go_to_mapa")

Answer 3

我解决了它没有动画：像这样的假：

100                 50                  100                 100
-82.5614380549815   -61.2386250164727   -70.8214933555803   -113.085294273425
63.4808523920134    71.2492107022344    40.2403909177619    123.906052225068
-43.1428254169980   -79.8465560431243   -8.86332933780633   -132.269515222896
21.9512910424390    86.8494877098212    -22.6803808332093   137.993637919124
-0.324547757386938  -92.1128384145929   53.7640196166716    -140.954822929939
-21.3110352832942   95.5328877966081    -83.7748031881502   141.094761269331
42.5230708505071    -97.0466778715188   112.116137495667    -138.418902426909
-62.8798722752104   96.6307163280550    -138.215550196187   132.992890319329
81.9803719854667    -94.2947890971016   161.559769097134    -124.926060504869
-99.4446392159052   90.0812551138450    -181.682036111080   114.372592711550
114.920836766971    -84.0716375263694   198.174987302179    -101.539954624572
-128.100385825296   76.3847285271368    -210.709163142815   86.6824352002572
138.720481894513    -67.1710769635203   219.033021842029    -70.0921219690280
-146.574502140440   56.6199063635580    -222.990477101486   52.1070327582791
151.516503440925    -44.9493339209586   222.520965582938    -33.0950981283072
-153.445319072891   32.3873778023315    -217.627693978053   13.4288556805328
152.307662312383    -19.1817679777499   208.387426508819    6.50027540164903
-148.121448302555   5.59183915228772    -194.975897304652   -26.2998808971022
140.970297553726    8.11485856302741    177.658703561865    45.5804419325655

prepareForSegue在swift中不起作用。我该如何解决？

3 个答案: