主表:
orderno status
====== ======
123 ACTIVE
456 INACTIVE
子表示例,我想选择新的和关闭状态:
orderno status
======= ======
123 NEW
123 CLOSE
123 PENDING
123 PENDING
结果:未选择行
子表示例,我想选择新的和关闭状态:
orderno status
======= ======
456 NEW
456 NEW
456 CLOSE
456 CLOSE
result2:成功选择orderno 456 out。
答案 0 :(得分:-1)
SELECT orderno,sum(decode(status,'NEW',0,'CLOSE',0,1))
FROM test1 group by orderno
having sum(decode(status,'NEW',0,'CLOSE',0,1))=0;
这是表数据(Test1)和o / p
123 NEW
123 CLOSE
123 PENDING
456 NEW
456 CLOSE
456 0