实现swift equatable协议给我带来了错误的访问错误。为什么?

时间:2015-05-06 23:36:23

标签: ios swift compiler-errors protocols

这是我的代码。似乎当我将UIColor子类化为使其等同时,我得到一个内存错误。那是为什么?

class MyColor: UIColor, Equatable {
    var name: String


    init(name: String, r: CGFloat, g: CGFloat, b: CGFloat, a: CGFloat = 1.0) {
        self.name = name
        super.init(red: r, green: g, blue: b, alpha: a)
    }

    required init(coder aDecoder: NSCoder) {
        fatalError("init(coder:) has not been implemented")
    }

}

func == (lhs: MyColor, rhs: MyColor) -> Bool {
    return lhs.name == rhs.name
}

let test1 = MyColor(name: "coolRed", r: 10, g: 12, b: 22)

let test2 = MyColor(name: "coolBlue", r: 10, g: 12, b: 22)


if test1 == test2 {
    println("hey")
}

enter image description here

1 个答案:

答案 0 :(得分:2)

UIColor 是一个类集群,应该避免使用子类。

您可以使用Objective-C运行时来获得所需的功能。

此片段是"游乐场准备就绪"。

import UIKit

let _nameKey = malloc(4)

extension UIColor : Equatable {

var name : String {
    get {
        return objc_getAssociatedObject(self, _nameKey) as! String
    }
    set {
         objc_setAssociatedObject(self,
            _nameKey,
            newValue,
            UInt(OBJC_ASSOCIATION_RETAIN_NONATOMIC)
        );
    }
}
}


public func ==(lhs: UIColor, rhs: UIColor) -> Bool {
    return lhs.name == rhs.name
}

let aRed = UIColor(red: 1.0, green: 0.0, blue: 0.0, alpha: 0.0)
aRed.name = "Red"
aRed.name

let anotherRed = UIColor(red: 1.0, green: 0.0, blue: 0.0, alpha: 0.0)
anotherRed.name = "Red"

aRed == anotherRed