Question

我有这个脚本，我正在使用，我上网并修改了一下。基本上我想要的是刮取收件箱中的所有电子邮件，并将其保存为CSV格式，其中包含电子邮件，名字，姓氏格式。到目前为止，它将所有信息保存到一列CSV而不是三列..

#!/usr/bin/env python
#
# Very basic example of using Python 3 and IMAP to iterate over emails in a
# gmail folder/label.  This code is released into the public domain.
#
# This script is example code from this blog post:
# http://www.voidynullness.net/blog/2013/07/25/gmail-email-with-python-via-imap/
#
# This is an updated version of the original -- modified to work with Python 3.4.
#
import sys
import imaplib
import getpass
import email
import email.header
import datetime
import csv


EMAIL_ACCOUNT = "test@email.com"

# Use 'INBOX' to read inbox.  Note that whatever folder is specified, 
# after successfully running this script all emails in that folder 
# will be marked as read.
EMAIL_FOLDER = "INBOX"


def process_mailbox(M):
    """
    Do something with emails messages in the folder.  
    For the sake of this example, print some headers.
    """

    rv, data = M.search(None, "ALL")
    if rv != 'OK':
        print("No messages found!")
        return

    emailList = []
    out = open('email_list.csv', 'w')
    for num in data[0].split():
        rv, data = M.fetch(num, '(RFC822)')
        if rv != 'OK':
            print("ERROR getting message", num)
            return

        msg = email.message_from_bytes(data[0][1]) # Contains all the message info including header and content
        hdr = email.header.make_header(email.header.decode_header(msg['From']))
        sender = str(hdr)
        emailList.append(sender)
        #out.write(sender)
        #out.write('\n')

    for c in emailList:
        print (c.split(" "))
        out.write(c)
        out.write('\n')

    out.close()


##        print('Raw Date:', msg['Date'])
##        # Now convert to local date-time
##        date_tuple = email.utils.parsedate_tz(msg['Date'])
##        if date_tuple:
##            local_date = datetime.datetime.fromtimestamp(
##                email.utils.mktime_tz(date_tuple))
##            print ("Local Date:", \
##                local_date.strftime("%a, %d %b %Y %H:%M:%S"))


M = imaplib.IMAP4_SSL('imap.gmail.com')

try:
    rv, data = M.login(EMAIL_ACCOUNT, 'password')
except imaplib.IMAP4.error:
    print ("LOGIN FAILED!!! ")
    sys.exit(1)

print(rv, data)

rv, mailboxes = M.list()
if rv == 'OK':
    print("Mailboxes:")
    print(mailboxes)

rv, data = M.select(EMAIL_FOLDER)
if rv == 'OK':
    print("Processing mailbox...\n")
    process_mailbox(M)
    M.close()
else:
    print("ERROR: Unable to open mailbox ", rv)

M.logout()

以这种格式打印出来：

['John', 'Doe', '<mail-noreply@google.com>']
['Joe', 'Doe', '<mail-noreply@google.com>']
['Jacob', 'Doe', '<mail-noreply@google.com>']
['Homer', 'Simpson-Doh!', '<mail-noreply@google.com>']

但在CSV中，它会将所有信息打印到一列中，如下所示：

      Column 1
Row 1 John Doe <mail-noreply@google.com>
Row 2 Joe Doe <mail-noreply@google.com>
Row 3 Jacob Doe <mail-noreply@google.com>

但我需要3列而不是..执行out.write（c.split（“”））但这会导致错误。

将电子邮件写入CSV导致只有一列

0 个答案: