带有新行“\ n”无法正常工作的php echo警告消息

Question

我想通过alert（）显示一条消息

$message = "No result found for the following info:Name: ".$FullName."IC: ".$ID." in database.";
echo "<script>alert('".$message."'); window.history.back();</script>";

这是有效的但是如果我在消息中添加一行新的'\ n'

$message = "No result found for the following info:\nName: ".$FullName."\nIC: ".$ID." in database.";

它不会显示弹出消息。有什么问题？

Answer 1

将其编辑为不更改为PHP中的换行符，而是改为javascript：

'No result found for the following info:\nName: '.$FullName.'\nIC: '.$ID.' in database.'
^                                               ^           ^      ^     ^             ^

或添加额外的反斜杠："\\n"。

据Panther说，也是事实：使用'alert("' . $message . '")'。

Answer 2

在换行符上添加另一个\反斜杠：

$message = "No result found for the following info:\\nName: ".$FullName."\\nIC: ".$ID." in database.";

Output

Answer 3

或者使用PHP_EOL

 $msg = 'Hello' . PHP_EOL . 'Next line';

Answer 4

\n等不是用单引号解释的，只是用双引号解释。

echo "<script>alert(\"" . $message . "\"); window.history.back();</script>";

OR

echo '<script>alert("' . $message . '"); window.history.back();</script>';

Answer 5

您需要使用Line feed + Newline

\r\n

，它将如以下脚本所示工作：

echo "If you view the source of output frame \r\n you will find a newline in this string.";
echo nl2br("You will find the \n newlines in this string \r\n on the browser window.");