OPENGL C#更改对象视图

时间:2015-04-20 13:58:19

标签: c# opengl

我在opengl中有一些对象,对象是在x位置查看,我想让它在y位置查看如何制作它? 这是代码

 Gl.glBegin(Gl.GL_TRIANGLES);


for (iogl = 0; (iogl <= 360); iogl = (iogl + 3))
            {
                Gl.glColor3f(1, 0, 0);
                Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * iogl), 4 * (float)Math.Cos(Math.PI / 180 * iogl), 25);
                Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), 4 * (float)Math.Cos(Math.PI / 180 * (iogl + 20)), 25);
                Gl.glVertex3f(0, 0, 35);
        }
        Gl.glEnd();
        Gl.glBegin(Gl.GL_QUADS);
        for (iogl = 0; (iogl <= 359); iogl++)
        {
            //Tabung
            Gl.glColor3f(1, 1, 1);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * iogl), 4 * (float)Math.Cos(Math.PI / 180 * iogl), 25);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * (iogl + 30)), 4 * (float)Math.Cos(Math.PI / 180 * (iogl + 30)), 25);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * iogl), 4 * (float)Math.Cos(Math.PI / 180 * iogl), 6);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * (iogl + 30)), 4 * (float)Math.Cos(Math.PI / 180 * (iogl + 30)), 6);





        }
        Gl.glEnd();


        Gl.glBegin(Gl.GL_QUADS);
        for (iogl = 0; (iogl <= 359); iogl++)
        {
            //Merah Tengah
            Gl.glColor3f(1, 0, 0);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * iogl), 4 * (float)Math.Cos(Math.PI / 180 * iogl), 6);
            Gl.glVertex3f(4 * (float)Math.Sin(Math.PI / 180 * (iogl + 30)), 3 * (float)Math.Cos(Math.PI / 180 * (iogl + 30)), 6);

            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * iogl), (3) * (float)Math.Cos(Math.PI / 180 * iogl), 3);
            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), (3) * (float)Math.Cos(Math.PI / 180 * (iogl + 20)), 3);


        }
        Gl.glEnd();

        Gl.glBegin(Gl.GL_QUADS);
        for (iogl = 0; (iogl <= 359); iogl++)
        {
            //PUTIH Belakang
            Gl.glColor3f(1, 1, 1);
            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * iogl), 3 * (float)Math.Cos(Math.PI / 180 * iogl), 3);
            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), 3 * (float)Math.Cos(Math.PI / 180 * (iogl + 20)), 3);
            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * iogl), 3 * (float)Math.Cos(Math.PI / 180 * iogl), -20);
            Gl.glVertex3f(3 * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), 3 * (float)Math.Cos(Math.PI / 180 * (iogl + 20)), -20);
        }
        Gl.glEnd();



        Gl.glBegin(Gl.GL_POLYGON);
        for (iogl = 0; (iogl <= 359); iogl++)
        {
            //putih alas Belakang
            Gl.glColor3f(1, 1, 1);
            Gl.glVertex3f(3.5f * (float)Math.Sin(Math.PI / 180 * iogl), 3.5f * (float)Math.Cos(Math.PI / 180 * iogl), -20);
            Gl.glVertex3f(3.5f * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), 3.5f * (float)Math.Cos(Math.PI / 180 * iogl + 20), -20);
            Gl.glVertex3f(3.5f * (float)Math.Sin(Math.PI / 180 * iogl), 3.5f * (float)Math.Cos(Math.PI / 180 * iogl), -25);
            Gl.glVertex3f(3.5f * (float)Math.Sin(Math.PI / 180 * (iogl + 20)), 3.5f * (float)Math.Cos(Math.PI / 180 * iogl + 20), -25);
        }
        Gl.glEnd();



        Gl.glBegin(Gl.GL_POLYGON);
        for (iogl = 0; (iogl <= 360); iogl = (iogl + 90))
        {
            Gl.glColor3f(1, 0, 0);
            Gl.glVertex3f(0, 0, -25);
            Gl.glVertex3f(0, 10 * (float)Math.Sin(Math.PI / 180 * iogl), -17);
            Gl.glVertex3f(10 * (float)Math.Cos(Math.PI / 180 * iogl), 0, -25);
            Gl.glVertex3f(0, 0, -25);
            Gl.glVertex3f(10 * (float)Math.Cos(Math.PI / 180 * iogl), 0, -17);
            Gl.glVertex3f(0, 10 * (float)Math.Sin(Math.PI / 180 * iogl), -25);
        }
        Gl.glEnd();

这里是对象是x位置的截图,我想让它(站立)在y位置我应该添加什么代码

ScreenShot

2 个答案:

答案 0 :(得分:0)

在开头调用glTranslatef函数。这将使矩阵倍增,您绘制的所有内容都将相对于平移坐标。

答案 1 :(得分:0)

在您的情况下,您需要围绕Z轴将火箭旋转90度,使其在y轴上站立。

如果你把这一行放在你发布的代码的开头,它应该可以工作。

GL.Rotate(90.0f, 0.0f, 0.0f, 1.0f);