Question

我的JSON如下所示。在总结之后，我找到了对numberOfPoint进行排序的方法。

    { "data": [
     {
        "id": {
            "year": 2015,
            "Name": "A"
        },
        "numberOfPoint": 2
    },
    {
        "id": {
            "year": 2014,
            "Name": "C"
        },
        "numberOfPoint": 2
    },
    {
        "id": {
            "year": 2014,
            "Name": "B"
        },
        "numberOfPoint": 2
    },
    {
        "id": {
            "year": 2014,
            "Name": "B"
        },
        "numberOfPoint": 2
    },
    {
        "id": {
            "year": 2013,
            "Name": "C"
        },
        "numberOfPoint": 2
    }]
}

obj是我的JSON。

var result = {};

obj.data.forEach(function (a) { result[a["id"]["Name"]] = (result[a["id"]["Name"]] || 0) + a["numberOfPoint"]; });

结果如下所示

{
    "A": 2,
    "C": 4,
    "B": 4
}

如何从最大到最小的数字点对此进行排序？我想要这样的结果。

{
    "B": 4,
    "C": 4,
    "A": 2
}

提前谢谢你。

Answer 1

也许这会有所帮助。

obj.data.sort(function(a, b) {
    return a.id.Name < b.id.Name;
});

for(var i in obj.data) {
    console.log(obj.data[i].id.Name);
}

Answer 2

您可以执行以下操作：

var result={
    "A": 2,
    "C": 4,
    "B": 4,
    "D": 3
}     

var temp = [];
$.each(result, function(key, value) {
    temp.push({v:value, k: key});
});
temp.sort(function(a,b){
   if(a.v < b.v){ return 1}
    if(a.v > b.v){ return -1}
      return 0;
});

$.each(temp, function(index, obj) {
    alert(obj.k + "-" + obj.v);
});

<强> Here is JSFiddle

Answer 3

var obj = { "data":  [
 {
    "id": {
        "year": 2015,
        "Name": "A"
    },
    "numberOfPoint": 2
},
{
    "id": {
        "year": 2014,
        "Name": "C"
    },
    "numberOfPoint": 2
},
{
    "id": {
        "year": 2014,
        "Name": "B"
    },
    "numberOfPoint": 2
},
{
    "id": {
        "year": 2014,
        "Name": "B"
    },
    "numberOfPoint": 2
},
{
    "id": {
        "year": 2013,
        "Name": "C"
    },
    "numberOfPoint": 2
}] }


var result = {};

obj.data.forEach(function (a) { 
   result[a["id"]["Name"]] = (result[a["id"]["Name"]] || 0) +   a["numberOfPoint"];
});

var temp = [];
$.each(result, function(key, value) {
  temp.push({v:value, k: key});
}); temp.sort(function(a,b){    if(a.v < b.v){ return 1}
if(a.v > b.v){ return -1}
  return 0; });

$.each(temp, function(index, obj) {
 alert(obj.k + "-" + obj.v); });

我希望你喜欢这个..如果你喜欢那就不要忘记投票给我......并感谢@Butani Vijay的好评。我已经共同实施了......

如何从JSON中对总结的数字进行排序

3 个答案: