Question

这是我的查询，

SELECT TOP (3) 
    a.INCIDENT_ID, a.REFERENCE, SUM(b.COST) AS TOTAL_COST
FROM          
    FDDC_T_D_INCIDENT AS a 
INNER JOIN
    FDDC_T_D_INCIDENT_COST AS b ON a.INCIDENT_ID = b.FINCIDENT_ID
WHERE        
    (a.CREATED_DATE >= @date1) AND (a.CREATED_DATE <= @date2)
GROUP BY 
    a.INCIDENT_ID
ORDER BY 
    TOTAL_COST DESC

我收到错误

专栏＆＃39; FDDC_T_D_INCIDENT.REFERENCE＆＃39;在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

有人可以帮我解决这个问题吗？

提前致谢！

Answer 1

试试这个：

SELECT        TOP (3) a.INCIDENT_ID, a.REFERENCE, SUM(b.COST) AS TOTAL_COST
FROM          FDDC_T_D_INCIDENT AS a INNER JOIN
              FDDC_T_D_INCIDENT_COST AS b ON a.INCIDENT_ID =b.FINCIDENT_ID
WHERE        (a.CREATED_DATE >= @date1) AND (a.CREATED_DATE <= @date2)
GROUP BY a.INCIDENT_ID, a.REFERENCE
ORDER BY TOTAL_COST DESC

您需要将“a.REFERENCE”添加到GROUP BY子句中。

编辑：

如果您只想要GROUP BY'a.INCIDENT_ID'：

，请尝试此操作

SELECT INCIDENT_ID, REFERENCE, TOTAL_COST
FROM(
        SELECT        TOP (3) a.INCIDENT_ID, a.REFERENCE, SUM(b.COST) AS TOTAL_COST
        FROM          FDDC_T_D_INCIDENT AS a INNER JOIN
                      FDDC_T_D_INCIDENT_COST AS b ON a.INCIDENT_ID =b.FINCIDENT_ID
        WHERE        (a.CREATED_DATE >= @date1) AND (a.CREATED_DATE <= @date2)
        GROUP BY a.INCIDENT_ID, a.REFERENCE
        ORDER BY TOTAL_COST DESC
    ) AS T
GROUP BY INCIDENT_ID

希望这有帮助。

Answer 2

尝试此操作，按Incident_ID分组并返回引用（如果事件有多个引用，将返回具有相同总成本的多行）。

SELECT TOP (3) 
    a.INCIDENT_ID, a.REFERENCE, SUM(b.COST) over (partition by a.incident_ID) AS TOTAL_COST
FROM          
    FDDC_T_D_INCIDENT AS a 
INNER JOIN
    FDDC_T_D_INCIDENT_COST AS b ON a.INCIDENT_ID = b.FINCIDENT_ID
WHERE        
    (a.CREATED_DATE >= @date1) AND (a.CREATED_DATE <= @date2)
ORDER BY 
    TOTAL_COST DESC

当我执行查询时，我收到“列名在选择列表中无效”错误

2 个答案: