Question

我一直在尝试使用javascript验证澳大利亚的电话号码，但它已经接受了所有内容。它需要10个数字长，从0接受空格开始：
02 4345 2334
和在一起 0243452334。
我认为正则表达式可能是错误的或代码本身

function PhoneNumberVal(form){
    var phoneFormat= /^0[0-8]{2})\)?[ ]?([0-9]{4})[ ]?([0-9]{4})$/;  
    var phoneLength = document.getElementById('phone').value.length;

    if(phoneFormat.test(phoneLength)) {
        return true;
    } else {
        alert("Not a valid phone number");
        return false;
    }
}

Answer 1

你的正则表达式错了。 ^0[0-8]{2})\)?[ ]?([0-9]{4})[ ]?([0-9]{4})$您未能使用左括号，因此您需要将[0-8]{2}更改为[0-8]，因为您的输入恰好包含10位数字。

^(?:\(0[0-8]\)|0[0-8])[ ]?[0-9]{4}[ ]?[0-9]{4}$

DEMO

Answer 2

正则表达式？哈！ Now you have two problems.

更新：此版本应为最终版。

这样做：

function IsAustralianTelephoneNumberValid(a_telephone)
{
    a_telephone = a_telephone.replace(/\s/g, ''); // remove all spaces

    // if is empty OR first char is NOT 0 
    if((a_telephone=='')||(a_telephone.charAt(0)!='0'))
    {
        alert("Not a valid phone number");
        return false;
    }

    // lets save the length of that string before we remove digits
    length_with_digits = a_telephone.length;

    // now string has its digits removed
    a_telephone = a_telephone.replace(/0|1|2|3|4|5|6|7|8|9/g,'');

    // if is nothing, then there was no other characters in string
    // except digits and spaces AND ALSO if the difference of length before the digits
    // removal and now is 10 then we can be sure we had 10 digits and nothing else,
    // so its valid. Any other case is not valid.
    if((a_telephone=='')&&(length_with_digits-a_telephone.length==10))
    {
        alert('ok');
        return true;
    }
    else
    {
        alert("Not a valid phone number");
        return false;
    }
}

http://jsfiddle.net/L7vzL4jm/10/

Answer 3

使用此正则表达式，

/^\D*0(\D*\d){9}\D*$/

<强> Demo

验证澳大利亚电话号码

3 个答案: