我有一个使用大量javascript的jsp,但速度不够快。我想首先优化它,这是代码的一部分:
在jsp我有初始化:
window.onload = function () {
formCollection.pageSize.value = "<%= pagingSize%>";
elemCollection = iDom3.Table.all["spis"].XML.DOM;
<% if (resultList != null) { %>
elementsNumber = <%= resultList.size() %>;
<%} else { %>
elementsNumber = 0;
<% } %>
contextPath = "<%= request.getContextPath() %>";
}
在我的js文件中,我有两种类型的js函数:
// gets the first element and sets it's value to all the other;
//the selectSingleNode function is used because I use XSLT transformation
//to generate the table
_setTehJed = function(){
var resultId = formCollection.elements["idTehJedinice_spis_1"].value;
var resultText = formCollection.elements["tehnicka_spis_1"].value;
if (resultId != ""){
var counter = 1;
while (counter<elementsNumber){
counter++;
if(formCollection.elements["idTehJedinice_spis_"+counter] != null){
formCollection.elements["idTehJedinice_spis_"+counter].value=resultId;
formCollection.elements["tehnicka_spis_"+counter].value=resultText;
}
var node=elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+counter+"']/data[@col = 'tehnicka']/title");
node.text=resultText;
var node2=elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+counter+"']/data[@col = 'idTehJedinice']/title");
node2.text=resultId;
}
}
}
// sets the elements checkbox to checked or unchecked
_SelectCheckRokCuvanja = {
all : [],
Item : function (oItem, sId) {
this.all["spis_"+sId] = oItem.value;
if (oItem.checked) {
elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+sId+"']/data[@col = 'rokCheck']").setAttribute("default", "true");
}else{
elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+sId+"']/data[@col = 'rokCheck']").setAttribute("default", "false");
}
}
}
我已经使用了这些提示:
http://blogs.msdn.com/b/ie/archive/2006/08/28/728654.aspx http://code.google.com/speed/articles/optimizing-javascript.html
但我仍然认为可以像定义这样的函数来完成一些事情:
在jsp中:
window.onload = function () {
iDom3.DigitalnaArhivaPrihvat.formCollection=document.forms["controller"];
iDom3.DigitalnaArhivaPrihvat.formCollection.pageSize.value = "<%= pagingSize%>";
iDom3.DigitalnaArhivaPrihvat.elemCollection = iDom3.Table.all["spis"].XML.DOM;
<% if (resultList != null) { %>
iDom3.DigitalnaArhivaPrihvat.elementsNumber = <%= resultList.size() %>
<%} else { %>
iDom3.DigitalnaArhivaPrihvat.elementsNumber = 0;
<% } %>
}
在js:
iDom3.DigitalnaArhivaPrihvat = {
formCollection:null,
elemCollection:null,
elementsNumber:null,
_setTehJed : function(){
var resultId = this.formCollection.elements.idTehJedinice_spis_1.value;
var resultText = this.formCollection.elements.tehnicka_spis_1.value;
if (resultId != ""){
var counter = 1;
while (counter<this.elementsNumber){
counter++;
if(this.formCollection.elements["idTehJedinice_spis_"+counter] !== null){
this.formCollection.elements["idTehJedinice_spis_"+counter].value=resultId;
this.formCollection.elements["tehnicka_spis_"+counter].value=resultText;
}
var node=this.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+counter+"']/data[@col = 'tehnicka']/title");
node.text=resultText;
var node2=this.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+counter+"']/data[@col = 'idTehJedinice']/title");
node2.text=resultId;
}
}
},
_SelectCheckRokCuvanja = {
all : [],
Item : function (oItem, sId) {
this.all["spis_"+sId] = oItem.value;
if (oItem.checked) {
this.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+sId+"']/data[@col = 'rokCheck']").setAttribute("default", "true");
}else{
this.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_"+sId+"']/data[@col = 'rokCheck']").setAttribute("default", "false");
}
}
}
但问题是作用域(如果我这样做,第二个函数没有正确执行)。有什么建议吗?
编辑:表格的数据结构:
<row id="spis_3">
<data col="rokCheck" type="check" default="false" onchange="_ChangeTypeRokCuvanje(this,'3')" >
<title>false</title>
<description>Tehnička jedinica</description>
</data>
答案 0 :(得分:3)
selectSingleNode()
是一项非常昂贵的操作。你应该尽量避免它。有两种解决方案:
自己迭代数据结构(因此您不必在DOM中搜索表,但可以直接逐行修改)。
由于您为每一行分配了一个ID,因此您应该能够在没有昂贵的XPath查找的情况下使用document.getElementById()
。
使用像jquery这样的框架一次获取所有相关节点( - >只进行1次昂贵的查找),然后遍历列表。
[编辑]有关如何实施#1的示例,请参阅Traversing an HTML table with JavaScript and DOM Interfaces。
答案 1 :(得分:1)
只需将this
的引用替换为_SelectCheckRokCuvanja
_SelectCheckRokCuvanja = {
all: [],
Item: function (oItem, sId) {
_SelectCheckRokCuvanja.all["spis_" + sId] = oItem.value;
if (oItem.checked) {
_SelectCheckRokCuvanja.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_" + sId + "']/data[@col = 'rokCheck']").setAttribute("default", "true");
} else {
_SelectCheckRokCuvanja.elemCollection.selectSingleNode("/suite/table/rows/row[@id = 'spis_" + sId + "']/data[@col = 'rokCheck']").setAttribute("default", "false");
}
}
}