Question

在django CreateView中，我有两个应该是唯一的字段。

即。说user和unique_name

要捕获完整性错误（当用户具有重复的unique_name时），我已经编写了try，除了正常的Django函数。它适用于HTML表单提交。但是，当我尝试使用Ajax提交表单时，我找不到捕获错误的方法。

class DataCreate(AjaxableResponseMixin,CreateView): model = Prescriptions fields = ['user','unique_name','x','y','z'] success_url = reverse_lazy('some url')



def form_valid(self, form):
    form.instance.user = self.request.user
    try:
        return super(DataCreate, self).form_valid(form)
    except IntegrityError:
        form.add_error('unique_name','You already have a user by that name')
        return render_to_response('html')

def save(self):
    request.session['unique_name'] = self.object.unique_name
    super(DataCreate,self).save() </code>


Note : Ajax Mixin is taken from Django Documentation(1.7) as follows.
 
class AjaxableResponseMixin(object):
    """
    Mixin to add AJAX support to a form.
    Must be used with an object-based FormView (e.g. CreateView)
    """
    def form_invalid(self, form):
        response = super(AjaxableResponseMixin, self).form_invalid(form)
        if self.request.is_ajax():
            return JsonResponse(form.errors, status=400)
        else:
            return response


def form_valid(self, form):
    # We make sure to call the parent's form_valid() method because
    # it might do some processing (in the case of CreateView, it will
    # call form.save() for example).
    response = super(AjaxableResponseMixin, self).form_valid(form)
    if self.request.is_ajax():
        data = {
            'pk': self.object.pk,
        }
        return JsonResponse(data)
    else:
        return response

def form_valid(self, form): form.instance.user = self.request.user try: return super(DataCreate, self).form_valid(form) except IntegrityError: form.add_error('unique_name','You already have a user by that name') return render_to_response('html') def save(self): request.session['unique_name'] = self.object.unique_name super(DataCreate,self).save() </code>

Answer 1

您应该在except子句中返回form_invalid而不是使用render_to_response

def form_valid(self, form):
    form.instance.user = self.request.user
    try:
        return super(DataCreate, self).form_valid(form)
    except IntegrityError:
        form.add_error('unique_name','You already have a user by that name')
        return self.form_invalid(form)

在ajax表单的django通用视图中捕获完整性错误

1 个答案: