Question

我已经多次尝试使用结构作为参数调用DLL函数，但没有一个成功。我使用的是Python 2.7.8。这是我的代码：

from ctypes import c_int, c_bool, WINFUNCTYPE, windll
from ctypes.wintypes import HWND, LPCSTR, UINT, sizeof
INPUT_PARM, OUTPUT_PARAM, INPUT_PARM_DEFAULT_ZERO = 1, 2, 4
prototype = WINFUNCTYPE(c_int, c_int, LPCSTR, LPCSTR, c_bool)
paramflags = ((INPUT_PARM, "Size", 0),
              (INPUT_PARM, "ProgrammerExe", r"C:\Program Files (x86)\ChipProgUSB\6_00_05\UprogNT2.exe"),
              (INPUT_PARM, "CommandLine", "/m"),
              (INPUT_PARM, "DebugMode", True))
Programmer = prototype(("ACI_Launch", windll.ACI), paramflags)
Programmer()

这是我正在进行的DLL调用的文档：

ACI_FUNC ACI_Launch(ACI_Launch_Params * params);
typedef struct tagACI_Launch_Params
{
 UINT   Size;             // (in)  Size of structure, in bytes
 LPCSTR ProgrammerExe;    // (in)  Programmer executable file name
 LPCSTR CommandLine;      // (in)  Optional programmer command-line parameters
 BOOL   DebugMode;        // (in)  Debug mode. Programmer window is not hidden
} ACI_Launch_Params;

错误是异常：访问冲突读取0x00000000 这看起来像是尝试使用Size作为指针，当我删除Size参数时，它的部分如下所示：

prototype = WINFUNCTYPE(c_int, LPCSTR, LPCSTR, c_bool)
paramflags = ((INPUT_PARM, "ProgrammerExe", ...

然后它给出：过程可能用太多的参数调用（超过8个字节）

该DLL可从phyton.com获得，作为演示。如果您查看硬件页面的底部，则有一个不需要任何注册的链接。

更新：在eryksun的帮助下，我解决了我的大错。但我仍然有一个问题，我现在不知道如何解决：

from ctypes import c_int, c_bool, WINFUNCTYPE, windll, Structure,POINTER, c_void_p
from ctypes.wintypes import HWND, LPCSTR, UINT, sizeof, HRESULT
class ACI_Launch_Params(Structure):
    _fields_ =  [("Size" , c_int), 
                 ("ProgrammerExe" , LPCSTR ),
                 ("CommandLine" , LPCSTR ),
                 ("DebugMode" , c_bool ),
                 ]
x=ACI_Launch_Params(64,r"C:\Program Files (x86)\ChipProgUSB\6_00_05\UprogNT2.exe","/m",False)

Launch = windll.ACI.ACI_Launch
Launch.argtypes = [POINTER(ACI_Launch_Params)]
Launch.restype = HRESULT
Exit = windll.ACI.ACI_Exit
Exit.argtypes = []
Exit.restype = HRESULT

print "start result",Launch(x)
time.sleep(4)

# prints Added for Debugging
print sizeof(x),x       #OK
print x.Size            #OK
print x._objects        #OK
print x.__sizeof__()    #Crash
print dir(x)            #Crash
print x.__dict__        #Crash
del x                   #Crash

print "stop result",Exit()
time.sleep(3)

这始终按预期启动应用程序，并且打印的返回值为0.但是在退出python代码时，它会崩溃python.exe。它似乎与结构“x＆＃39;被删除，如果我之前删除它，那么它会在那时崩溃。我猜测DLL正在释放结构，但如果是这种情况，我该如何才能可靠地运行？

事件记录器报告： Faulting application name: python.exe, version: 0.0.0.0, time stamp: 0x53b1ecd8 Faulting module name: python27.dll, version: 2.7.8150.1013, time stamp: 0x53b1ecd6 Exception code: 0xc0000005 Fault offset: 0x00031fe5 Faulting process id: 0x62d8

Python ctypes问题调用DLL函数的参数

0 个答案: