Question

我有以下XML数据：

<?xml version="1.0" encoding="UTF-8" ?>
<?xml-stylesheet type="text/xsl" href="serverReserve_1.xsl" ?>
  <!--
To change this license header, choose License Headers in Project Properties.
To change this template file, choose Tools | Templates
and open the template in the editor.
-->


  <reservation xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="localSchema.xsd">
    <new>
      <name>Ah Huat</name>
      <icNum>930330033330</icNum>
      <contact>0182345679</contact>
      <reserveDate>20150402</reserveDate>
      <reserveTime>08:00am</reserveTime>
      <day>4</day>
      <totalPeople>2</totalPeople>
      <room unit="2" type="King Suite">
        <bedType>King Bed</bedType>
        <extraRequirement>One more quilt</extraRequirement>
        <extraRequirement>One more bed</extraRequirement>
      </room>
    </new>

    <new>
      <name>Ah Huat</name>
      <icNum>930330033330</icNum>
      <contact>0182345679</contact>
      <reserveDate>20150402</reserveDate>
      <reserveTime>08:00am</reserveTime>
      <day>4</day>
      <totalPeople>2</totalPeople>
      <room unit="2" type="King Suite">
        <bedType>King Bed</bedType>
        <extraRequirement>One more quilt</extraRequirement>
        <extraRequirement>One more bed</extraRequirement>
      </room>
    </new>

    <new>
      <name>Ah Huat</name>
      <icNum>930330033330</icNum>
      <contact>0182345679</contact>
      <reserveDate>20150414</reserveDate>
      <reserveTime>08:00am</reserveTime>
      <day>4</day>
      <totalPeople>2</totalPeople>
      <room unit="2" type="King Suite">
        <bedType>King Bed</bedType>
        <extraRequirement>One more quilt</extraRequirement>
        <extraRequirement>One more bed</extraRequirement>
      </room>
    </new>

    <delete>
      <name>Hoo Chee Sem</name>
      <icNum>930110011101</icNum>
      <reserveDate>20150411</reserveDate>
      <reserveTime>08:00am</reserveTime>
      <room unit="2" type="Hillview Deluxe">
        <bedType>2 Single Bed</bedType>
      </room>
    </delete>

    <roomList>
      <rooms code="R1">Single Room</rooms>
      <rooms code="R2">Double Room</rooms>
      <rooms code="R3">Twin Room</rooms>
      <rooms code="R4">Duplex Room</rooms>
      <rooms code="R5">King Suite</rooms>
      <rooms code="R6">Hillview Deluxe</rooms>
      <rooms code="R7">Seaview Deluxe</rooms>
    </roomList>

    <bedList>
      <beds code="B1">Single Bed</beds>
      <beds code="B2">2 Single Beds</beds>
      <beds code="B3">King Bed</beds>
      <beds code="B4">2 King Beds</beds>
      <beds code="B5">Queen Bed</beds>
      <beds code="B6">2 Queen Beds</beds>
      <beds code="B7">3 Queen Beds</beds>
    </bedList>
  </reservation>

在XSLT 1.0中，我想通过reserveDate进行分组并计算reserveDate的计数。因此，在上述数据中，我需要一个表格，显示reserveDate和该日期的预订总数。

如何在XSLT 1.0中执行此操作？当我尝试使用这种方法时，它给了我一个错误，说“解析XSLT样式表失败了。”

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:output method="html" />
  <xsl:output method="html" indent="yes" />

  <xsl:template match="/">
    <html>

    <head>
      <title>reserve.xsl</title>
    </head>

    <body>
      <xsl:key name="groups" match="/reservation/new" use="reserveDate" />

      <xsl:template match="/reservation">
        <xsl:apply-templates select="new[generate-id() = generate-id(key('groups', reserveDate)[1])]" />
      </xsl:template>
      <xsl:template match="new">
        <h1>
                        <xsl:value-of select="reserveDate"/>
                    </h1>
        <table id="{reserveDate}">
          <tr class="heading">
            <th scope="col">Member Id</th>
            <th scope="col">First Name</th>
            <th scope="col">Last Name</th>
          </tr>
          <xsl:for-each select="key('groups', reserveDate)">
            <tr>
              <td>
                <xsl:value-of select="name" />
              </td>
              <td>
                <xsl:value-of select="reserveTime" />
              </td>
              <td>
                <xsl:value-of select="contact" />
              </td>
            </tr>
          </xsl:for-each>
        </table>
      </xsl:template>
    </body>

    </html>
  </xsl:template>

</xsl:stylesheet>

Answer 1

您可以按如下方式修改XSLT - 在匹配根级别的模板之外移动匹配reservation的模板：

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">    
<xsl:output method="html" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
  <xsl:key name="groups" match="/reservation/new" use="reserveDate" />
  <xsl:template match="/">
    <hmtl>
      <head>
        <title>reserve.xsl</title>
      </head>
      <body>
        <xsl:apply-templates/>
      </body>
    </hmtl>
    </xsl:template>
    <xsl:template match="/reservation">
    ....
    </xsl:template>
</xsl:stylesheet>

在匹配根目录的模板中，apply templates将调用匹配reservation的模板：

<body>
  <xsl:apply-templates/>
</body>

Demo

XSLT 1.0 Group by reservationDate

1 个答案: